java.lang.IllegalArgumentException：org.hibernate.hql.internal.ast.QuerySyntaxException：未映射用户 [来自用户]
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User]
我收到 java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User] 错误。我已经解决了这些问题，但没有帮助我。
org.hibernate.hql.internal.ast.QuerySyntaxException: table 未映射
Hibernate 错误 - QuerySyntaxException：未映射用户 [来自用户]
Database table image:
数据库Tableuser.jpg
UserBean.java
封装模型；
import java.util.ArrayList;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
import controller.Login;
import controller.userinfo;
import gfgshfhjdgfhjdhhjfhjd.iModel;
@Entity
@Table(name= "User")
public class UserBean implements iModel
{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name="Id")
private int id;
@Column(name="Username")
private String username ;
@Column(name="Password")
private String password ;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public UserBean(){}
public ArrayList<?> getData() {
return userinfo.getUser();
}
}
Userinfo.java
package controller;
import java.util.ArrayList;
import java.util.List;
import org.hibernate.Session;
import model.UserBean;
import test.HibernateSessionFactory;
public class Userinfo {
public static void saveUser(UserBean user) {
Session session = HibernateSessionFactory.getSessionFactory().openSession();
session.beginTransaction();
session.save(user);
session.getTransaction().commit();
}
public static ArrayList<?> getUser() {
Session session = HibernateSessionFactory.getSessionFactory().openSession();
session.beginTransaction();
List<UserBean> list = (List<UserBean>)session.createQuery("from User").list();
ArrayList<String> list2= new ArrayList<String>();
for(int i=0;i<list.size();i++) {
int tmp = list.get(i).getId();
StringBuilder sBuilder = new StringBuilder();
sBuilder.append(tmp);
list2.add(sBuilder.toString());
list2.add(list.get(i).getUsername());
list2.add(list.get(i).getPassword());
}
if (list != null) {
for (int i = 0; i < list.size(); i++) {
System.out.println("User ID : " + list.get(i).getId());
System.out.println("User First Name : "+ list.get(i).getUsername());
System.out.println("User Last Name : "+ list.get(i).getPassword());
}
}
session.getTransaction().commit();
return list2;
}
}
hibernate.cfg.xml
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- SQL Dialect -->
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- Database Connection Settings -->
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/project</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password"></property>
<property name="show_sql">true</property>
<!-- Specifying Session Context -->
<property name="hibernate.current_session_context_class">org.hibernate.context.internal.ThreadLocalSessionContext</property>
<!-- <property name="hibernate.hbm2ddl.auto">create</property> -->
<!-- Mapping With Model Class Containing Annotations -->
<mapping class="model.UserBean" />
</session-factory>
</hibernate-configuration>
Error Log:
May 06, 2018 4:16:04 PM org.hibernate.hql.internal.QueryTranslatorFactoryInitiator initiateService
INFO: HHH000397: Using ASTQueryTranslatorFactory
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User]
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:133)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:157)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:164)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:670)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:103)
at controller.Userinfo.getUser(Userinfo.java:28)
at model.UserBean.getData(UserBean.java:55)
at controller.Login.doGet(Login.java:38)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:635)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1041)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:603)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2430)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2419)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
at java.lang.Thread.run(Thread.java:745)
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User]
at org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79)
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:217)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:141)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:77)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:153)
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:553)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:662)
... 26 more
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped
at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:169)
at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:91)
at org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:79)
at org.hibernate.hql.internal.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:326)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3706)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3595)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:720)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:576)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:313)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:266)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:189)
... 32 more
请帮忙..谢谢
正如我从您的数据库方案中看到的那样，UserBean.java 中的列映射名称不正确（例如 @Column(name="Username")，但它应该是小写的）。可能 table name.
同样的问题
可能是原因
第二个可能的选项是您没有向 Hibernate 指示结果实体是什么。为此，请将 createQuery("from User") 替换为 createQuery("from UserBean", UserBean.class)
@Table(name = ...) 区分（结果 SQL）table 名字，兄弟！
@Entity(name = ...) 区分 "entity name" 尤其是在 jpql/hql/criteria 查询中 - 默认为 class 名称。 – @xerx593
我收到 java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User] 错误。我已经解决了这些问题，但没有帮助我。
org.hibernate.hql.internal.ast.QuerySyntaxException: table 未映射
Hibernate 错误 - QuerySyntaxException：未映射用户 [来自用户]
Database table image:
数据库Tableuser.jpg
UserBean.java
封装模型；
import java.util.ArrayList;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
import controller.Login;
import controller.userinfo;
import gfgshfhjdgfhjdhhjfhjd.iModel;
@Entity
@Table(name= "User")
public class UserBean implements iModel
{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name="Id")
private int id;
@Column(name="Username")
private String username ;
@Column(name="Password")
private String password ;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public UserBean(){}
public ArrayList<?> getData() {
return userinfo.getUser();
}
}
Userinfo.java
package controller;
import java.util.ArrayList;
import java.util.List;
import org.hibernate.Session;
import model.UserBean;
import test.HibernateSessionFactory;
public class Userinfo {
public static void saveUser(UserBean user) {
Session session = HibernateSessionFactory.getSessionFactory().openSession();
session.beginTransaction();
session.save(user);
session.getTransaction().commit();
}
public static ArrayList<?> getUser() {
Session session = HibernateSessionFactory.getSessionFactory().openSession();
session.beginTransaction();
List<UserBean> list = (List<UserBean>)session.createQuery("from User").list();
ArrayList<String> list2= new ArrayList<String>();
for(int i=0;i<list.size();i++) {
int tmp = list.get(i).getId();
StringBuilder sBuilder = new StringBuilder();
sBuilder.append(tmp);
list2.add(sBuilder.toString());
list2.add(list.get(i).getUsername());
list2.add(list.get(i).getPassword());
}
if (list != null) {
for (int i = 0; i < list.size(); i++) {
System.out.println("User ID : " + list.get(i).getId());
System.out.println("User First Name : "+ list.get(i).getUsername());
System.out.println("User Last Name : "+ list.get(i).getPassword());
}
}
session.getTransaction().commit();
return list2;
}
}
hibernate.cfg.xml
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- SQL Dialect -->
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- Database Connection Settings -->
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/project</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password"></property>
<property name="show_sql">true</property>
<!-- Specifying Session Context -->
<property name="hibernate.current_session_context_class">org.hibernate.context.internal.ThreadLocalSessionContext</property>
<!-- <property name="hibernate.hbm2ddl.auto">create</property> -->
<!-- Mapping With Model Class Containing Annotations -->
<mapping class="model.UserBean" />
</session-factory>
</hibernate-configuration>
Error Log:
May 06, 2018 4:16:04 PM org.hibernate.hql.internal.QueryTranslatorFactoryInitiator initiateService
INFO: HHH000397: Using ASTQueryTranslatorFactory
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User]
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:133)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:157)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:164)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:670)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:103)
at controller.Userinfo.getUser(Userinfo.java:28)
at model.UserBean.getData(UserBean.java:55)
at controller.Login.doGet(Login.java:38)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:635)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1041)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:603)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2430)
at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2419)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
at java.lang.Thread.run(Thread.java:745)
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [from User]
at org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79)
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:217)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:141)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:77)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:153)
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:553)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:662)
... 26 more
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped
at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:169)
at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:91)
at org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:79)
at org.hibernate.hql.internal.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:326)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3706)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3595)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:720)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:576)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:313)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:266)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:189)
... 32 more
请帮忙..谢谢
正如我从您的数据库方案中看到的那样，UserBean.java 中的列映射名称不正确（例如 @Column(name="Username")，但它应该是小写的）。可能 table name.
可能是原因
第二个可能的选项是您没有向 Hibernate 指示结果实体是什么。为此，请将 createQuery("from User") 替换为 createQuery("from UserBean", UserBean.class)
@Table(name = ...) 区分（结果 SQL）table 名字，兄弟！
@Entity(name = ...) 区分 "entity name" 尤其是在 jpql/hql/criteria 查询中 - 默认为 class 名称。 – @xerx593