使用 web-inspector 检测用户是否更改了某些内容
Detect if user changes something with web-inspector
有什么方法可以检测用户是否使用 web-inspector 进行了任何更改?
例如,用户打开检查器并更改 div 中的文本以伪造它。有什么方法可以检测到吗?
刷新页面以查看网站上的原始内容,因为网络检查员所做的更改未存储在服务器上。
如果您只有几个要观看的元素,请使用 MutationObserver
。
mozilla 文档中的示例用法:
// Select the node that will be observed for mutations
var targetNode = document.getElementById('some-id');
// Options for the observer (which mutations to observe)
var config = { attributes: true, childList: true };
// Callback function to execute when mutations are observed
var callback = function(mutationsList) {
for(var mutation of mutationsList) {
if (mutation.type == 'childList') {
console.log('A child node has been added or removed.');
}
else if (mutation.type == 'attributes') {
console.log('The ' + mutation.attributeName + ' attribute was modified.');
}
}
};
// Create an observer instance linked to the callback function
var observer = new MutationObserver(callback);
// Start observing the target node for configured mutations
observer.observe(targetNode, config);
// Later, you can stop observing
observer.disconnect();
有什么方法可以检测用户是否使用 web-inspector 进行了任何更改? 例如,用户打开检查器并更改 div 中的文本以伪造它。有什么方法可以检测到吗?
刷新页面以查看网站上的原始内容,因为网络检查员所做的更改未存储在服务器上。
如果您只有几个要观看的元素,请使用 MutationObserver
。
mozilla 文档中的示例用法:
// Select the node that will be observed for mutations
var targetNode = document.getElementById('some-id');
// Options for the observer (which mutations to observe)
var config = { attributes: true, childList: true };
// Callback function to execute when mutations are observed
var callback = function(mutationsList) {
for(var mutation of mutationsList) {
if (mutation.type == 'childList') {
console.log('A child node has been added or removed.');
}
else if (mutation.type == 'attributes') {
console.log('The ' + mutation.attributeName + ' attribute was modified.');
}
}
};
// Create an observer instance linked to the callback function
var observer = new MutationObserver(callback);
// Start observing the target node for configured mutations
observer.observe(targetNode, config);
// Later, you can stop observing
observer.disconnect();