使用条件对连接查询进行序列化

Sequelize join query with condition

我正在使用以下语法来 select 一些记录:

models.account.findAll({
  attributes: ['password'],
  include: [{
    model: models.user,
    as : 'user'
  }],
  where: {
    'password': password,
    'user.email': email
  }
}).then(function(res){
  console.log(res);
});

它正在生成以下查询:

SELECT * 
FROM   `accounts` AS `account` 
    LEFT OUTER JOIN `users` AS `user` 
        ON `account`.`user_id` = `user`.`id` 
WHERE  `account`.`password` = 'PASSWORD' 
    AND `account`.`user.email` = 'xyz@gmail.com';
        ^^^^^^^^^^^^^^^^^^^^^^

所以它给我一个错误:Unknown column 'account.user.email' in 'where clause'。我只想 user.email 在 WHERE 子句中。预期的查询应该是:

SELECT * 
FROM   `accounts` AS `account` 
    LEFT OUTER JOIN `users` AS `user` 
        ON `account`.`user_id` = `user`.`id` 
WHERE  `account`.`password` = 'PASSWORD' 
    AND `user`.`email` = 'xyz@gmail.com';

我做错了什么?

将用户 table 的 where 过滤器放入包含部分:

models.account.findAll({
  attributes: ['password'],
  include: [{
    model: models.user,
    where: {
      email: email
    }
  }],
  where: {
    password: password
  }
}).then(function(res){
  console.log(res);
});