NSCoding 和 Codable 可以共存吗?
Can NSCoding and Codable co-exist?
在测试新的 Codable 如何与 NSCoding 交互时,我整理了一个游乐场测试,涉及使用包含 Codable 结构的 Class 的 NSCoding。惠特
struct Unward: Codable {
var id: Int
var job: String
}
class Akward: NSObject, NSCoding {
var name: String
var more: Unward
init(name: String, more: Unward) {
self.name = name
self.more = more
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "name")
aCoder.encode(more, forKey: "more")
}
required init?(coder aDecoder: NSCoder) {
name = aDecoder.decodeObject(forKey: "name") as? String ?? ""
more = aDecoder.decodeObject(forKey: "more") as? Unward ?? Unward(id: -1, job: "unk")
super.init()
}
}
var upone = Unward(id: 12, job: "testing")
var adone = Akward(name: "Adrian", more: upone)
以上内容已被 Playground 接受,不会产生任何编译器错误。
但是,如果我像这样尝试 Saving adone:
let encodeit = NSKeyedArchiver.archivedData(withRootObject: adone)
Playground 立即崩溃并出现错误:
error: Execution was interrupted, reason: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0).
为什么?
有没有办法让 NSCoding class 包含 Codable 结构?
您得到的实际错误是:
-[_SwiftValue encodeWithCoder:]: unrecognized selector sent to instance
这是来自以下行:
aCoder.encode(more, forKey: "more")
问题的原因是more
(类型Unward
)不符合NSCoding
。但是一个Swift struct
不能符合NSCoding
。除了符合 NSCoding
之外,您还需要将 Unward
更改为扩展 NSObject
的 class。 None 这影响了符合 Codable
的能力。
这是您更新后的 classes:
class Unward: NSObject, Codable, NSCoding {
var id: Int
var job: String
init(id: Int, job: String) {
self.id = id
self.job = job
}
func encode(with aCoder: NSCoder) {
aCoder.encode(id, forKey: "id")
aCoder.encode(job, forKey: "job")
}
required init?(coder aDecoder: NSCoder) {
id = aDecoder.decodeInteger(forKey: "id")
job = aDecoder.decodeObject(forKey: "job") as? String ?? ""
}
}
class Akward: NSObject, Codable, NSCoding {
var name: String
var more: Unward
init(name: String, more: Unward) {
self.name = name
self.more = more
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "name")
aCoder.encode(more, forKey: "more")
}
required init?(coder aDecoder: NSCoder) {
name = aDecoder.decodeObject(forKey: "name") as? String ?? ""
more = aDecoder.decodeObject(forKey: "more") as? Unward ?? Unward(id: -1, job: "unk")
}
}
你的测试值:
var upone = Unward(id: 12, job: "testing")
var adone = Akward(name: "Adrian", more: upone)
您现在可以归档和取消归档:
let encodeit = NSKeyedArchiver.archivedData(withRootObject: adone)
let redone = NSKeyedUnarchiver.unarchiveObject(with: encodeit) as! Akward
并且你可以编码和解码:
let enc = try! JSONEncoder().encode(adone)
let dec = try! JSONDecoder().decode(Akward.self, from: enc)
现有答案并没有真正解决互操作性问题,而是展示了如何从 NSCoding
迁移到 Codable
。
我有一个 use-case,但这不是一个选项,我确实需要在 Codable
上下文中使用 NSCoding
。如果您好奇:我需要在我的 Mac 应用程序的 XPC 服务之间发送模型,并且这些模型包含 NSImage
s。我本可以制作一堆 serialize/deserialize 图像的 DTO,但那会是很多样板。此外,这是 属性 包装器的完美用例。
这是我想出的 属性 包装器:
@propertyWrapper
struct CodableViaNSCoding<T: NSObject & NSCoding>: Codable {
struct FailedToUnarchive: Error { }
let wrappedValue: T
init(wrappedValue: T) { self.wrappedValue = wrappedValue }
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
let data = try container.decode(Data.self)
let unarchiver = try NSKeyedUnarchiver(forReadingFrom: data)
unarchiver.requiresSecureCoding = Self.wrappedValueSupportsSecureCoding
guard let wrappedValue = T(coder: unarchiver) else {
throw FailedToUnarchive()
}
unarchiver.finishDecoding()
self.init(wrappedValue: wrappedValue)
}
func encode(to encoder: Encoder) throws {
let archiver = NSKeyedArchiver(requiringSecureCoding: Self.wrappedValueSupportsSecureCoding)
wrappedValue.encode(with: archiver)
archiver.finishEncoding()
let data = archiver.encodedData
var container = encoder.singleValueContainer()
try container.encode(data)
}
private static var wrappedValueSupportsSecureCoding: Bool {
(T.self as? NSSecureCoding.Type)?.supportsSecureCoding ?? false
}
}
下面是我为它编写的简单测试:
import Quick
import Nimble
import Foundation
@objc(FooTests_SampleNSCodingClass)
private class SampleNSCodingClass: NSObject, NSCoding {
let a, b, c: Int
init(a: Int, b: Int, c: Int) {
self.a = a
self.b = b
self.c = c
}
required convenience init?(coder: NSCoder) {
self.init(
a: coder.decodeInteger(forKey: "a"),
b: coder.decodeInteger(forKey: "b"),
c: coder.decodeInteger(forKey: "c")
)
}
func encode(with coder: NSCoder) {
coder.encode(a, forKey: "a")
coder.encode(b, forKey: "b")
coder.encode(c, forKey: "c")
}
}
@objc(FooTests_SampleNSSecureCodingClass)
private class SampleNSSecureCodingClass: SampleNSCodingClass, NSSecureCoding {
static var supportsSecureCoding: Bool { true }
}
private struct S<T: NSObject & NSCoding>: Codable {
@CodableViaNSCoding
var sampleNSCodingObject: T
}
class CodableViaNSCodingSpec: QuickSpec {
override func spec() {
context("Used with a NSCoding value") {
let input = S(sampleNSCodingObject: SampleNSCodingClass(a: 123, b: 456, c: 789))
it("round-trips correctly") {
let encoded = try JSONEncoder().encode(input)
let result = try JSONDecoder().decode(S<SampleNSCodingClass>.self, from: encoded)
expect(result.sampleNSCodingObject.a) == 123
expect(result.sampleNSCodingObject.b) == 456
expect(result.sampleNSCodingObject.c) == 789
}
}
context("Used with a NSSecureCoding value") {
let input = S(sampleNSCodingObject: SampleNSSecureCodingClass(a: 123, b: 456, c: 789))
it("round-trips correctly") {
let encoded = try JSONEncoder().encode(input)
let result = try JSONDecoder().decode(S<SampleNSSecureCodingClass>.self, from: encoded)
expect(result.sampleNSCodingObject.a) == 123
expect(result.sampleNSCodingObject.b) == 456
expect(result.sampleNSCodingObject.c) == 789
}
}
}
}
一些注意事项:
如果你需要走另一条路(将 Codable
对象嵌入到 NSCoding
存档中),你可以使用添加到 [=19= 的现有方法]/NSDecoder
这是为每个对象创建一个新的存档。除了在 encoding/decoding 期间添加相当多的对象分配外,它还可能使结果膨胀(在我的测试中,空存档大约为 220 字节)。
Codable
从根本上说比 NSCoding
更受限制。 Codable
以一种只能处理具有值语义的对象的方式实现。结果:
- 具有别名的对象图(对同一对象的多次引用)将导致被反对的对象重复
- 带循环的对象图永远无法解码(会无限递归)
这意味着您不能真正围绕 NSCoder
/NSCoder
类 制作 Encoder
/Decoder
包装器(如 NSKeyedArchiver
/NSKeyedUnarchiver
),而不需要大量记账来检测这些场景和 fatalError
。 (这也意味着您不能支持 archiving/unarchiving 任何通用 NSCoding
对象,只能支持那些没有别名或循环的对象)。这就是为什么我采用“制作独立存档并将其编码为 Data
”方法的原因。
在测试新的 Codable 如何与 NSCoding 交互时,我整理了一个游乐场测试,涉及使用包含 Codable 结构的 Class 的 NSCoding。惠特
struct Unward: Codable {
var id: Int
var job: String
}
class Akward: NSObject, NSCoding {
var name: String
var more: Unward
init(name: String, more: Unward) {
self.name = name
self.more = more
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "name")
aCoder.encode(more, forKey: "more")
}
required init?(coder aDecoder: NSCoder) {
name = aDecoder.decodeObject(forKey: "name") as? String ?? ""
more = aDecoder.decodeObject(forKey: "more") as? Unward ?? Unward(id: -1, job: "unk")
super.init()
}
}
var upone = Unward(id: 12, job: "testing")
var adone = Akward(name: "Adrian", more: upone)
以上内容已被 Playground 接受,不会产生任何编译器错误。
但是,如果我像这样尝试 Saving adone:
let encodeit = NSKeyedArchiver.archivedData(withRootObject: adone)
Playground 立即崩溃并出现错误:
error: Execution was interrupted, reason: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0).
为什么? 有没有办法让 NSCoding class 包含 Codable 结构?
您得到的实际错误是:
-[_SwiftValue encodeWithCoder:]: unrecognized selector sent to instance
这是来自以下行:
aCoder.encode(more, forKey: "more")
问题的原因是more
(类型Unward
)不符合NSCoding
。但是一个Swift struct
不能符合NSCoding
。除了符合 NSCoding
之外,您还需要将 Unward
更改为扩展 NSObject
的 class。 None 这影响了符合 Codable
的能力。
这是您更新后的 classes:
class Unward: NSObject, Codable, NSCoding {
var id: Int
var job: String
init(id: Int, job: String) {
self.id = id
self.job = job
}
func encode(with aCoder: NSCoder) {
aCoder.encode(id, forKey: "id")
aCoder.encode(job, forKey: "job")
}
required init?(coder aDecoder: NSCoder) {
id = aDecoder.decodeInteger(forKey: "id")
job = aDecoder.decodeObject(forKey: "job") as? String ?? ""
}
}
class Akward: NSObject, Codable, NSCoding {
var name: String
var more: Unward
init(name: String, more: Unward) {
self.name = name
self.more = more
}
func encode(with aCoder: NSCoder) {
aCoder.encode(name, forKey: "name")
aCoder.encode(more, forKey: "more")
}
required init?(coder aDecoder: NSCoder) {
name = aDecoder.decodeObject(forKey: "name") as? String ?? ""
more = aDecoder.decodeObject(forKey: "more") as? Unward ?? Unward(id: -1, job: "unk")
}
}
你的测试值:
var upone = Unward(id: 12, job: "testing")
var adone = Akward(name: "Adrian", more: upone)
您现在可以归档和取消归档:
let encodeit = NSKeyedArchiver.archivedData(withRootObject: adone)
let redone = NSKeyedUnarchiver.unarchiveObject(with: encodeit) as! Akward
并且你可以编码和解码:
let enc = try! JSONEncoder().encode(adone)
let dec = try! JSONDecoder().decode(Akward.self, from: enc)
现有答案并没有真正解决互操作性问题,而是展示了如何从 NSCoding
迁移到 Codable
。
我有一个 use-case,但这不是一个选项,我确实需要在 Codable
上下文中使用 NSCoding
。如果您好奇:我需要在我的 Mac 应用程序的 XPC 服务之间发送模型,并且这些模型包含 NSImage
s。我本可以制作一堆 serialize/deserialize 图像的 DTO,但那会是很多样板。此外,这是 属性 包装器的完美用例。
这是我想出的 属性 包装器:
@propertyWrapper
struct CodableViaNSCoding<T: NSObject & NSCoding>: Codable {
struct FailedToUnarchive: Error { }
let wrappedValue: T
init(wrappedValue: T) { self.wrappedValue = wrappedValue }
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
let data = try container.decode(Data.self)
let unarchiver = try NSKeyedUnarchiver(forReadingFrom: data)
unarchiver.requiresSecureCoding = Self.wrappedValueSupportsSecureCoding
guard let wrappedValue = T(coder: unarchiver) else {
throw FailedToUnarchive()
}
unarchiver.finishDecoding()
self.init(wrappedValue: wrappedValue)
}
func encode(to encoder: Encoder) throws {
let archiver = NSKeyedArchiver(requiringSecureCoding: Self.wrappedValueSupportsSecureCoding)
wrappedValue.encode(with: archiver)
archiver.finishEncoding()
let data = archiver.encodedData
var container = encoder.singleValueContainer()
try container.encode(data)
}
private static var wrappedValueSupportsSecureCoding: Bool {
(T.self as? NSSecureCoding.Type)?.supportsSecureCoding ?? false
}
}
下面是我为它编写的简单测试:
import Quick
import Nimble
import Foundation
@objc(FooTests_SampleNSCodingClass)
private class SampleNSCodingClass: NSObject, NSCoding {
let a, b, c: Int
init(a: Int, b: Int, c: Int) {
self.a = a
self.b = b
self.c = c
}
required convenience init?(coder: NSCoder) {
self.init(
a: coder.decodeInteger(forKey: "a"),
b: coder.decodeInteger(forKey: "b"),
c: coder.decodeInteger(forKey: "c")
)
}
func encode(with coder: NSCoder) {
coder.encode(a, forKey: "a")
coder.encode(b, forKey: "b")
coder.encode(c, forKey: "c")
}
}
@objc(FooTests_SampleNSSecureCodingClass)
private class SampleNSSecureCodingClass: SampleNSCodingClass, NSSecureCoding {
static var supportsSecureCoding: Bool { true }
}
private struct S<T: NSObject & NSCoding>: Codable {
@CodableViaNSCoding
var sampleNSCodingObject: T
}
class CodableViaNSCodingSpec: QuickSpec {
override func spec() {
context("Used with a NSCoding value") {
let input = S(sampleNSCodingObject: SampleNSCodingClass(a: 123, b: 456, c: 789))
it("round-trips correctly") {
let encoded = try JSONEncoder().encode(input)
let result = try JSONDecoder().decode(S<SampleNSCodingClass>.self, from: encoded)
expect(result.sampleNSCodingObject.a) == 123
expect(result.sampleNSCodingObject.b) == 456
expect(result.sampleNSCodingObject.c) == 789
}
}
context("Used with a NSSecureCoding value") {
let input = S(sampleNSCodingObject: SampleNSSecureCodingClass(a: 123, b: 456, c: 789))
it("round-trips correctly") {
let encoded = try JSONEncoder().encode(input)
let result = try JSONDecoder().decode(S<SampleNSSecureCodingClass>.self, from: encoded)
expect(result.sampleNSCodingObject.a) == 123
expect(result.sampleNSCodingObject.b) == 456
expect(result.sampleNSCodingObject.c) == 789
}
}
}
}
一些注意事项:
如果你需要走另一条路(将
Codable
对象嵌入到NSCoding
存档中),你可以使用添加到 [=19= 的现有方法]/NSDecoder
这是为每个对象创建一个新的存档。除了在 encoding/decoding 期间添加相当多的对象分配外,它还可能使结果膨胀(在我的测试中,空存档大约为 220 字节)。
Codable
从根本上说比NSCoding
更受限制。Codable
以一种只能处理具有值语义的对象的方式实现。结果:- 具有别名的对象图(对同一对象的多次引用)将导致被反对的对象重复
- 带循环的对象图永远无法解码(会无限递归)
这意味着您不能真正围绕
NSCoder
/NSCoder
类 制作Encoder
/Decoder
包装器(如NSKeyedArchiver
/NSKeyedUnarchiver
),而不需要大量记账来检测这些场景和fatalError
。 (这也意味着您不能支持 archiving/unarchiving 任何通用NSCoding
对象,只能支持那些没有别名或循环的对象)。这就是为什么我采用“制作独立存档并将其编码为Data
”方法的原因。