在页面上列出博主 post，图片和风格化为 css

Question

下面的代码用于在标签名称中列出博主 post 但它只列出了 post 的标题，我想知道是否可以将 post 图像一起显示，并使用 css 进行样式化，我该怎么做？在 /feeds/posts/summary/-/NAME?alt=json&callback=processPostList12&start-index=" 中，您可以更改标签名称，并且只会显示与标签名称关联的 post。

我更改了代码以创建 class 并将图像的位置更改为行的开头，但现在它不再按字母顺序排列，我尝试了所有我知道的并且无法修复它。图像是否也可能指向post？正如标题

这是我更改的部分：

          a1E.href = url;
          a1E.textContent = title;
          a1E.className += "aclass";
          postImage.src = imageThumb;
          postImage.className += "imclass";

  var startIndex = 1;
  var maxResults = 150;
  var allResults = [];
  function sendQuery12()
  {
    var scpt = document.createElement("script");
    scpt.src = "/feeds/posts/summary/-/Series?alt=json&callback=processPostList13&start-index=" + startIndex + "&max-results=" + maxResults;
    document.body.appendChild(scpt);
  }
  function printArrayResults(root)
  { 
    //Sort Alphebetically
    allResults.sort(function(a, b){
      var a_string = a.children[0].textContent ;
      var b_string = b.children[0].textContent ;
      if(a_string < b_string) return -1;
      if(a_string > b_string) return 1;
      return 0;
    })
    var elmt = document.getElementById("postList13");
    for (index = 0; index < allResults.length; index++) {
      elmt.appendChild(allResults[index]);
    }
  }
  function processPostList13(root)
  {   
    var elmt = document.getElementById("postList13");
    if (!elmt)
      return;
    var feed = root.feed;
    if (feed.entry.length > 0)
    {
      for (var i = 0; i < feed.entry.length; i++)
      {
        var entry = feed.entry[i];
        var title = entry.title.$t;
        var date = entry.published.$t;

        if( entry.media$thumbnail != undefined ){
          var imageThumb = entry.media$thumbnail.url ;
        } else {
          var imageThumb = 'https://i.imgur.com/PqPqZQN.jpg' ;
        }

        for (var j = 0; j < entry.link.length; j++)
        {
          if (entry.link[j].rel == "alternate")
          {
            var url = entry.link[j].href;
            if (url && url.length > 0 && title && title.length > 0)
            {
              var liE = document.createElement("li");
              var a1E = document.createElement("a");
              var postImage = document.createElement("img");

              a1E.href = url;
              a1E.textContent = title;
              a1E.className += "aclass";
              postImage.src = imageThumb;
              postImage.className += "imclass";

              liE.appendChild(postImage);
              liE.appendChild(a1E);



              //elmt.appendChild(liE);
              allResults.push(liE);

            }
            break;
          }
        }
      }
      if (feed.entry.length >= maxResults)
      {
        startIndex += maxResults;
        sendQuery12();
      } else {
        printArrayResults();
      }
    }
  }
  sendQuery12();

<div class="postlist1" id="postList13">
</div>

Answer 1

1- 从 APi

中检索 post 图像

在这些行之后：

var entry = feed.entry[i];
var title = entry.title.$t;
var date  = entry.published.$t;

你可以使用：

var imageThumb = entry.media$thumbnail.url;

它将检索 post 的第一个图像缩略图。你应该验证它，因为没有图像的 posts 将 return undefined for media$thumbnail 并会导致 javascript 错误。所以 :

if( entry.media$thumbnail != undefined ){
    var imageThumb = entry.media$thumbnail.url;
} else {
    var imageThumb = 'alternative_image_path' ;
}

2- 附加 post 图片：

...
var postImage= document.createElement("img");
postImage.src = imageThumb;
liE.appendChild(postImage);
...

最终代码应该是这样的：

<div>
  <ul id="postList12"></ul>
</div>
<script type="text/javascript">
  var startIndex = 1;
  var maxResults = 150;
  var allResults = [];
  function sendQuery12()
  {
    var scpt = document.createElement("script");
    scpt.src = "/feeds/posts/summary/-/NAME?alt=json&callback=processPostList12&start-index=" + startIndex + "&max-results=" + maxResults;
    document.body.appendChild(scpt);
  }
  function printArrayResults(root)
  { 
    //Sort Alphebetically
    allResults.sort(function(a, b){
      var a_string = a.children[0].textContent ;
      var b_string = b.children[0].textContent ;
      if(a_string < b_string) return -1;
      if(a_string > b_string) return 1;
      return 0;
    })
    var elmt = document.getElementById("postList12");
    for (index = 0; index < allResults.length; index++) {
      elmt.appendChild(allResults[index]);
    }
  }
  function processPostList12(root)
  {   
    var elmt = document.getElementById("postList12");
    if (!elmt)
      return;
    var feed = root.feed;
    if (feed.entry.length > 0)
    {
      for (var i = 0; i < feed.entry.length; i++)
      {
        var entry = feed.entry[i];
        var title = entry.title.$t;
        var date = entry.published.$t;

        if( entry.media$thumbnail != undefined ){
          var imageThumb = entry.media$thumbnail.url ;
        } else {
          var imageThumb = 'https://i.imgur.com/PqPqZQN.jpg' ;
        }

        for (var j = 0; j < entry.link.length; j++)
        {
          if (entry.link[j].rel == "alternate")
          {
            var url = entry.link[j].href;
            if (url && url.length > 0 && title && title.length > 0)
            {
              var liE = document.createElement("li");
              var a1E = document.createElement("a");
              var postImage = document.createElement("img");

              a1E.href = url;
              a1E.textContent = title;
              postImage.src = imageThumb;

              liE.appendChild(a1E);
              liE.appendChild(postImage);

              //elmt.appendChild(liE);
              allResults.push(liE);

            }
            break;
          }
        }
      }
      if (feed.entry.length >= maxResults)
      {
        startIndex += maxResults;
        sendQuery12();
      } else {
        printArrayResults();
      }
    }
  }
  sendQuery12();
</script>

在页面上列出博主 post，图片和风格化为 css

Listing blogger post on a page, with image and stylize with css

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javascript

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