Sequelize 关系错误

Question

我正在写一个带有 sequelize 和 postgresl 的 express API，postgresl 托管在 Heroku。

当我尝试在下面的这些表之间建立关系时，出现了这个错误

Unhandled rejection SequelizeDatabaseError: relation "questions" does not exist

这个想法是一个问题有一个 id、一个标题、一个分数、有很多答案和一个正确答案。

问题模型：

import { sequelize } from "../Util/db"
import { Users } from "./User"
import { Answer } from "./Answer"
const Sequelize = require("sequelize")
const Question = sequelize.define("question", {
  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
    autoIncrement: true
  },
  title: {
    type: Sequelize.STRING
  },
  score: {
    type: Sequelize.INTEGER,
    defaultValue: 0
  },
  content: {
    type: Sequelize.JSONB
  }
})

Question.belongsTo(Users)
Question.hasMany(Answer, { as: "Answers", foreignKey: "id"})
Question.hasOne(Answer, {as: "RightAnswer", foreignKey: "id"})
Question.sync({force: false}).then(() => {
  // Table created
  console.log("Question Table Synchronized")
})


interface QuestionType {
  id: number
  title: string
  score: number
  content: string
}


export { Question, QuestionType }

答案模型：

import { sequelize } from "../Util/db"
import { Users } from "./User"
import { Question } from "./Question"
const Sequelize = require("sequelize")
const Answer = sequelize.define("answer", {
  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
    autoIncrement: true
  },
  score: {
    type: Sequelize.INTEGER,
    defaultValue: 0
  },
  content: {
    type: Sequelize.JSONB
  }
})

Answer.belongsTo(Users)
Answer.sync({force: false}).then(() => {
  // Table created
  console.log("Answer Table Synchronized")
})


interface AnswerType {
  id: number
  score: number
  content: string
}


export { Answer, AnswerType }

创建脚本，由sequelize创建

Executing (default): CREATE TABLE IF NOT EXISTS "users" ("id"  SERIAL , "email" VARCHAR(255), "score" INTEGER DEFAULT 0, "name" VARCHAR(255), "createdAt" TIMESTAMP WITH TIME ZONE NOT NULL, "updatedAt" TIMESTAMP WITH TIME ZONE NOT NULL, PRIMARY KEY ("id"));
Executing (default): CREATE TABLE IF NOT EXISTS "answers" ("id"  SERIAL  REFERENCES "questions" ("id") ON DELETE CASCADE ON UPDATE CASCADE, "score" INTEGER DEFAULT 0, "content" JSONB, "createdAt" TIMESTAMP WITH TIME ZONE NOT NULL, "updatedAt" TIMESTAMP WITH TIME ZONE NOT NULL, "userId" INTEGER REFERENCES "users" ("id") ON DELETE SET NULL ON UPDATE CASCADE, PRIMARY KEY ("id"));
Executing (default): CREATE TABLE IF NOT EXISTS "questions" ("id"  SERIAL , "title" VARCHAR(255), "score" INTEGER DEFAULT 0, "content" JSONB, "createdAt" TIMESTAMP WITH TIME ZONE NOT NULL, "updatedAt" TIMESTAMP WITH TIME ZONE NOT NULL, "userId" INTEGER REFERENCES "users" ("id") ON DELETE SET NULL ON UPDATE CASCADE, PRIMARY KEY ("id"));
Executing (default): SELECT i.relname AS name, ix.indisprimary AS primary, ix.indisunique AS unique, ix.indkey AS indkey, array_agg(a.attnum) as column_indexes, array_agg(a.attname) AS column_names, pg_get_indexdef(ix.indexrelid) AS definition FROM pg_class t, pg_class i, pg_index ix, pg_attribute a WHERE t.oid = ix.indrelid AND i.oid = ix.indexrelid AND a.attrelid = t.oid AND t.relkind = 'r' and t.relname = 'users' GROUP BY i.relname, ix.indexrelid, ix.indisprimary, ix.indisunique, ix.indkey ORDER BY i.relname;
Unhandled rejection SequelizeDatabaseError: relation "questions" does not exist
    at Query.formatError (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/sequelize/lib/dialects/postgres/query.js:363:16)
    at query.catch.err (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/sequelize/lib/dialects/postgres/query.js:86:18)
    at tryCatcher (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/util.js:16:23)
    at Promise._settlePromiseFromHandler (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/promise.js:512:31)
    at Promise._settlePromise (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/promise.js:569:18)
    at Promise._settlePromise0 (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/promise.js:614:10)
    at Promise._settlePromises (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/promise.js:689:18)
    at Async._drainQueue (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/async.js:133:16)
    at Async._drainQueues (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/async.js:143:10)
    at Immediate.Async.drainQueues (/home/mazzardo/Codigo/pas/node-typescript-boilerplate/node_modules/bluebird/js/release/async.js:17:14)
    at runCallback (timers.js:651:20)
    at tryOnImmediate (timers.js:624:5)
    at processImmediate [as _immediateCallback] (timers.js:596:5)
Executing (default): SELECT i.relname AS name, ix.indisprimary AS primary, ix.indisunique AS unique, ix.indkey AS indkey, array_agg(a.attnum) as column_indexes, array_agg(a.attname) AS column_names, pg_get_indexdef(ix.indexrelid) AS definition FROM pg_class t, pg_class i, pg_index ix, pg_attribute a WHERE t.oid = ix.indrelid AND i.oid = ix.indexrelid AND a.attrelid = t.oid AND t.relkind = 'r' and t.relname = 'questions' GROUP BY i.relname, ix.indexrelid, ix.indisprimary, ix.indisunique, ix.indkey ORDER BY i.relname;
User Table Synchronized
Question Table Synchronized

旁注，我在项目中使用打字稿

Answer 1

这可能是因为每个 sync 的竞争条件。每次以异步方式调用 sync，并且由于我们有外键约束，因此可能未创建正在寻找关联的 table 之一。我认为你应该使用

sequelize.sync() 这应该可以解决您的问题。

来自docs

Because Sequelize is doing a lot of magic, you have to call Sequelize.sync after setting the associations! Doing so will allow you the following:

Sequelize 关系错误

Sequelize relationship error

postgresql

express

sequelize.js

heroku-postgres