在 python 中生成随机句子

Question

我对 python 和编程还很陌生！

我需要编写一个包含 4 个元组的程序，每个元组有 5 个元素。一个元组应该有动词，一个元组应该有名词，一个元组应该有形容词，一个元组应该有副词。然后我必须使用 0 到 4 之间随机生成的数字从每个元组中选择一个元素。这是我目前所拥有的：

import random

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")
num = random.randrange(0,5)
print (num)

有人可以告诉我我做错了什么吗？

Answer 1

如果你想 select 每个元组的索引总是相同，那么试试这样的事情：

import random
idx = random.randrange(0, 5)
print ("%s %s %s %s"%(nouns[idx], verbs[idx], adv[idx], adj[idx]))

如果您想为每个元组获取随机元素，以下应该可行：

import random
print("%s %s %s %s"%(random.choice(nouns), random.choice(verbs), random.choice(adv), random.choice(adj))

Answer 2

num = random.randrange(0,5)   
print (num)

只是给你你生成的随机数。您需要使用这样生成的随机数来访问元组。

print(nouns[num])
print(verbs[num])
print(adv[num])
print(adj[num])

Answer 3

您可以在列表理解中使用 random.choice，然后将所选列表与 join:

连接起来

>>> l=[nouns,verbs,adj,adv]
>>> ' '.join([random.choice(i) for i in l])
'girl runs dirty crazily.'
>>> ' '.join([random.choice(i) for i in l])
'monkey hits clueless occasionally.'

Answer 4

最简单的理解方式：

import random

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")
num = random.randrange(0,5)
print nouns[num] + ' ' + verbs[num] + ' ' + adv[num] + ' ' + adj[num]

Answer 5

我会按如下方式使用 random.choice，因为它比 random.randrange...

更好

words = (adj, nouns, verb, adv)
sentence = "".join(choice(word) for word in words)

Answer 6

对于与 returns 所有可能排列的已接受答案类似的功能：

import random

def make_random_sentence():
  nouns = ["puppy", "car", "rabbit", "girl", "monkey"]
  verbs = ["runs", "hits", "jumps", "drives", "barfs"]
  adv = ["crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally."]
  adj = ["adorable", "clueless", "dirty", "odd", "stupid"]

  random_entry = lambda x: x[random.randrange(len(x))]
  return " ".join([random_entry(nouns), random_entry(verbs), random_entry(adv), random_entry(adj)])

Answer 7

random.choice 是 select 列表、元组或类似容器中的随机事物。最后一行所做的是 select 从每个列表中随机选择一个东西，然后根据选择创建一个新列表。然后打印该列表。在循环中，无论用户输入多少次，都会执行 X 次。

from random import choice 

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")

# asking user as to how many sentences he would like to generate 
for _ in range (int (input ("Enter integer value :"))): 
    print(list(map(choice, [nouns, verbs, adv, adj])))

Enter integer value :2
['car', 'barfs', 'dutifully.', 'odd']
['rabbit', 'runs', 'occasionally.', 'clueless']

[Program finished]

Answer 8

这是一个简单的。如果您想要多个句子，请使用：

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")

print(nouns[random.randrange(0,5)] + ' ' + verbs[random.randrange(0,5)] + ' ' 
+ adv[random.randrange(0,5)] + ' ' + adj[random.randrange(0,5)])

在 python 中生成随机句子

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