⊥ 在共识协议中是什么意思？
What does ⊥ mean in a consensus protocol?
我正在阅读 Ben Or 的算法，我想知道第 7 行中 bp := ⊥ 的含义？这是整个算法
我不确定你为什么被否决，但我能猜到的最好原因是这可能更适合 math.stackexchange.com。参见 https://math.stackexchange.com/questions/658262/what-is-the-correct-reading-of-bot for an explanation of the symbol and this page for some additional information to the protocol: http://www.nada.kth.se/kurser/kth/2D5340/wwwbook/node17.html
我不熟悉 Ben Or 的算法，但上面链接的页面似乎对符号的使用有合理的解释：
In order to get an intuition of how randomization is used, suppose
that the inputs are split in half; half of them being zeroes and half
of them being ones. In this case, every process will set its b-value
to ⊥ (line 7). Since all b-values are ⊥, each process will
set the next a-value at random. With high probability, about half of
the new a-values will be zeroes and about half will be ones. Which
again will force a random determination of all new a-values, and so
on.
按照逻辑，bp := ⊥表示bp未定
我正在阅读 Ben Or 的算法，我想知道第 7 行中 bp := ⊥ 的含义？这是整个算法
我不确定你为什么被否决，但我能猜到的最好原因是这可能更适合 math.stackexchange.com。参见 https://math.stackexchange.com/questions/658262/what-is-the-correct-reading-of-bot for an explanation of the symbol and this page for some additional information to the protocol: http://www.nada.kth.se/kurser/kth/2D5340/wwwbook/node17.html
我不熟悉 Ben Or 的算法，但上面链接的页面似乎对符号的使用有合理的解释：
In order to get an intuition of how randomization is used, suppose that the inputs are split in half; half of them being zeroes and half of them being ones. In this case, every process will set its b-value to ⊥ (line 7). Since all b-values are ⊥, each process will set the next a-value at random. With high probability, about half of the new a-values will be zeroes and about half will be ones. Which again will force a random determination of all new a-values, and so on.
按照逻辑，bp := ⊥表示bp未定