从 Wikipedia API 获取图像，除了 .svg 扩展名

Question

我正在尝试从我的 PHP 页面中的维基百科 API 中提取图像。但是我在 .svg 扩展名中得到了一些不必要的图像。有什么办法可以避免使用 .svg 扩展名或仅包含 api 请求中的 .jpg 扩展名？我可以看到一个名为 mediatype 的变量，但它不起作用。

我正在使用以下 api 请求 url:

 https://en.wikipedia.org/w/api.php?&redirects=1&action=query&titles=Basilica%20Cistern&prop=images&format=json&imlimit=15

我得到的回复如下：

{
  "continue": {
    "imcontinue": "1365761|Peacock-eyed_column_in_the_Basilica_Cistern_in_Istanbul,Turkey,January_20,2014.jpg ",
    "continue ": " || "
  },
  "query": {
    "pages": {
      "1365761": {
        "pageid": 1365761,
        "ns": 0,
        "title": "Basilica Cistern",
        "images": [{
            "ns": 6,
            "title": "File:20131203 Istanbul 269.jpg"
          },
          {
            "ns": 6,
            "title": "File:Archaeological site icon (red).svg"
          },
          {
            "ns": 6,
            "title": "File:Basilica Cistern.jpg"
          },
          {
            "ns": 6,
            "title": "File:Basilica Cistern Constantinople 2007.jpg"
          },
          {
            "ns": 6,
            "title": "File:Basilica Cistern Constantinople 2007 011.jpg"
          },
          {
            "ns": 6,
            "title": "File:Basilica cistern Art.jpg"
          },
          {
            "ns": 6,
            "title": "File:Carp at the Basilica Cistern, Istanbul 2007.JPG"
          },
          {
            "ns": 6,
            "title": "File:Commons-logo.svg"
          },
          {
            "ns": 6,
            "title": "File:Head of Medusa, Basilica Cistern, Constantinople 01.jpg"
          },
          {
            "ns": 6,
            "title": "File:Head of Medusa, Basilica Cistern, Constantinople 02.jpg"
          },
          {
            "ns": 6,
            "title": "File:Location map Istanbul.png"
          }
        ]
      }
    }
  }
}

PHP 代码：

function getResults($json){

$results = array();

$json_array = json_decode($json, true);

foreach($json_array['query']['pages'] as $page){
    if(count($page['images']) > 0){
        foreach($page['images'] as $image){

            $title = str_replace(" ", "_", $image["title"]);
            $imageinfourl = "https://en.wikipedia.org/w/api.php?&action=query&titles=".$title."&prop=imageinfo&iiprop=url&format=json";
            $imageinfo = curl($imageinfourl);
            $iamge_array = json_decode($imageinfo, true);
            $image_pages = $iamge_array["query"]["pages"];


            foreach($image_pages as $a){

                $results[] = $a["imageinfo"][0]["url"];
            }
        }
    }
}

return $results;

}

Answer 1

在 API 中看不到任何内容。我想也许你可以使用 imimages 参数，但它只对匹配整个 title 有用，例如

...&imimages=File%3A20131203%20Istanbul%20269.jpg

您可以过滤结果

// snip
if(count($page['images']) > 0) {
    $jpgs = array_filter($page['images'], function($img) {
        return strtolower(pathinfo($img['title'], PATHINFO_EXTENSION)) === 'jpg';
    });

    foreach($jpgs as $image) {
        // and continue

或者，只需检查 foreach 循环中的扩展程序

foreach($page['images'] as $image) {
    if (strtolower(pathinfo($img['title'], PATHINFO_EXTENSION)) !== 'jpg') {
        continue;
    }

从 Wikipedia API 获取图像，除了 .svg 扩展名

Fetching Images from Wikipedia API except .svg extension

php

api

wikipedia-api