Django

Question

views.py

class BHA_UpdateView(UpdateView):
    model = BHA_List
    pk_url_kwarg = 'pk_alt'
    form_class = BHA_overall_Form

forms.py

class BHA_overall_Form(forms.ModelForm):
    class Meta():
        model = BHA_overall
        fields = '__all__'

models.py

class BHA_List(models.Model):
    well = models.ForeignKey(WellInfo, 'CASCADE', related_name='bha_list')
    bha_number = models.CharField(max_length=100)

class BHA_overall(models.Model):
    bha_number = models.ForeignKey(BHA_List, 'CASCADE', related_name='bha_overall')
    drill_str_name = models.CharField(max_length=111)
    depth_in = models.CharField(max_length=111)
    depth_out = models.CharField(max_length=111)

如果我在模板中使用 {{ form.as_p }} 向用户显示表单字段，它将生成如下所示的页面：

如何覆盖 get() 或 post() 方法以获取用户输入、保存用户输入并更新特定模型实例？

对于我当前的 views.py，来自 forms 的用户输入不会保存到数据库，因为我的 form 指的是 model = BHA_overall，而我的模型 views.py 是 model = BHA_List。但出于某种原因，我不想在 views.py 中更改我的模型。

如果我将 CBV 更改为 CreateView 而不是 UpdateView，它将毫无问题地为数据库创建一个新的 BHA_overall 实例。但是如果我想更新BHA_overall的特定模型实例，我首先需要get()一个BHA_overall的模型实例，然后通过post()更新模型实例。但我不知道该怎么做。我该怎么办？

编辑：

像这样：

def post():
    bha_overall_instance1.bha_number = userinput.bha_number
    bha_overall_instance1.drill_str_name = userinput.drill_str_name
    bha_overall_instance1.depth_in = userinput.depth_in

Answer 1

您也可以只使用

from django.views import View

和你的views.py：

from django.views import View
from django.models import Model1, Model2
class UpdateView(View):
      model = Model1
      template_name = 'update.html'

      def post(self, request, id, name , "other-parameters", ..., *kwargs):
          obj1 = self.model1.objects.get_or_404(id=id) # this just example you can past any parameters that you want
          if obj1:
             obj1.name = name # updating name of obj1
             obj1.save() # savin updated object
          obj2 = Model2.objects.get_or_404(id=request.POST.get('id') # you must to pass name='some-id' in your template at input tag
          if obj2:
             obj2.some_field = some_parameter
             obj2.save()
          return redirect('index/') # you must choose only url that exists

我等你的反馈

Django - 强制表单保存到特定模型

Django - force form to save to a specific model

django-models

django-forms

django-views

django-class-based-views