将字符串变量拆分为 16 个字符长的块

Question

我有点python菜鸟！我试图将一个字符串（长度在 0 到 32 个字符之间）拆分为两个 16 个字符的块，并将每个块保存为一个单独的变量，但我不知道如何做。

这是我的意思的伪代码概述：

text = "The weather is nice today"
split 'text' into two 16-character blocks, 'text1' and 'text2'
print(text1)
print(text2)

这将输出以下内容：

The weather is n
ice today

我正在显示在连接到 raspberry pi 的 2x16 字符 LCD 上输入的文本，我需要将文本分成几行以写入 LCD - 我正在将文本写入 LCD，例如这：lcd.message(text1 "\n" text2)所以块的长度必须正好是 16 个字符。

Answer 1

text = "The weather is nice today"

text1, text2 = text[:16], text[16:32]
print(text1)
print(text2)

打印：

The weather is n
ice today

Answer 2

可以通过指定索引将文本分成两个字符串变量。 [:16] 基本上是 0 到 15，[16:] 是 16 到字符串中的最后一个字符

text1 = text[:16]
text2 = text[16:]

Answer 3

text = "The weather is nice today"

text1, text2 = [text[i: i + 16] for i in range(0, len(text), 16)]

print(text1)
print(text2)

它将打印：

The weather is n
ice today

Answer 4

尝试这样的事情：

s = "this is a simple string that is long"
size = 8
for sl in range(0, int(len(s)/size)):
   out = s[sl:sl + size]
   print(out, len(out))

Answer 5

一个字符串就像一个列表。

您可以拆分它或计算字符串中的字符数。

示例：

word = 'www.BellezaCulichi.com'


total_characters = len(word)

print(str(total_characters))
# it show 22, 22 characters has word

您可以拆分字符串并获取前 5 个字符

print(word[0:5])
# it shows:  www.B
# the first 5 characters in the string



print(word[0:15])
# split the string and get the 15 first characters
# it shows:  www.BellezaCuli
# the first 5 characters in the string

您可以将拆分结果存储在变量中：

first_part = word[0:15]

Answer 6

这适用于任何 text

text = "The weather is nice today"
splitted = [text[i:i+16] for i  in range(0, len(text), 16)]
print (splitted) # Will print all splitted elements together

或者你也可以这样做

text = "The weather is nice today"
for i in range(0, len(text), 16):
    print (text[i:i+16])

将字符串变量拆分为 16 个字符长的块

Splitting a string variable into chunks 16 characters long

python

string

split

lcd

raspberry-pi