无法让 myDescription 值显示在 MainLabel 上,JSON API
Can't get myDescription value to be shown on MainLabel, JSON API
我在 Swift 中为 iOS 制作了一个天气应用程序 4,我正在使用 OpenWeatherMap API 将 JSON 数据解析到应用程序,我有让大部分应用程序正常工作,用户输入一个城市,并显示天气。我有当前温度、当前风速、当前湿度,我正在尝试使当前描述正常工作,但无法显示。
我想让 MainLabel 显示当前的天气描述,但我无法让它工作。代码的顶部是来自 API 键的 JSON 数据,描述在天气部分。我试过 MainLabel.Weather?.Description 但它会打印出完整的描述、ID、Main 和 Icon 值。我将不胜感激。谢谢
这是我用来解码来自 OpenWeatherMap JSON 数据的结构 API:
JSON 结构如下:
import UIKit
//Below is the JSON data from the OpenWeatherMap API
struct Coordinate : Decodable {
let lat, lon : Double?
}
struct Weather : Decodable {
var id : Int?
var main, myDescription, icon : String?
enum CodingKeys : String, CodingKey {
case id = "id"
case main = "main"
case icon = "icon"
case myDescription = "description"
}
}
struct Sys : Decodable {
let type, id : Int?
let sunrise, sunset : Date?
let message : Double?
let country : String?
}
struct Main : Decodable {
let temp, tempMin, tempMax : Double?
let pressure, humidity : Int?
}
struct Wind : Decodable {
let speed : Double?
let deg : Int?
}
struct MyWeather : Decodable {
let coord : Coordinate?
let cod, visibility, id : Int?
let name : String?
let base : String?
let weather : [Weather]?
let sys : Sys?
let main : Main?
let wind : Wind?
let dt : Date?
}
查看下面的控制器:
class ViewController: UIViewController {
@IBOutlet weak var HumidityLabel: UILabel!
@IBOutlet weak var MainLabel: UILabel!
@IBOutlet weak var WindLabel: UILabel!
@IBOutlet weak var TempLabel: UILabel!
@IBOutlet weak var LocationLabel: UILabel!
//
@IBOutlet weak var userValue: UITextField!
//Assigning Labels
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
@IBAction func GoButton(_ sender: Any) {
let text: String = userValue.text!
guard let APIUrl = URL(string: "https://api.openweathermap.org/data/2.5/weather?q=" + text + "&appid=*********APIKEY*********&units=Metric") else { return }
//API KEY
URLSession.shared.dataTask(with: APIUrl) { data, response, error in
guard let data = data else { return }
let decoder = JSONDecoder()
//Decoder
do {
let weatherData = try decoder.decode(MyWeather.self, from: data)
if (self.MainLabel != nil)
{
if let gmain = weatherData.weather?.description {
print(gmain)
DispatchQueue.main.async {
self.MainLabel.text! = String (describing: gmain)
}
}
}
if (self.LocationLabel != nil)
{
if let gmain = weatherData.name {
print(gmain)
DispatchQueue.main.async {
self.LocationLabel.text! = "Current Weather in: " + String (gmain)
}
}
}
if (self.HumidityLabel != nil)
{
if let ghumidity = weatherData.main?.humidity
{
print(ghumidity, "THIS IS HUMIDITY")
DispatchQueue.main.async {
self.HumidityLabel.text! = String (ghumidity)
}
}
}
if (self.WindLabel != nil)
{
if let gspeed = weatherData.wind?.speed {
print(gspeed, "THIS IS THE SPEED")
DispatchQueue.main.async {
self.WindLabel.text! = String(gspeed) + " mph"
}
}
}
if (self.TempLabel != nil)
{
if let ggtemp = weatherData.main?.temp {
print(ggtemp, "THIS IS THE TEMP")
DispatchQueue.main.async {
self.TempLabel.text! = String (ggtemp) + " c"
}
}
}
} catch {
print(error.localizedDescription)
}
}.resume()
}
}
通读您的视图控制器代码,您似乎正试图将 weatherData.weather.description
中的值加载到您的标签中,这将是 Weather
对象数组的描述,而不是实际的您从 JSON 响应中解析的值。
查看 Weather
对象,您正在将 JSON 响应中的 'description' 值解析为 myDescription
属性 Weather
对象,Weather
对象放置在 weatherData
对象的数组中。
因此您需要从数组中的对象中获取该值,而不是简单地打印包含 Weather
对象的数组描述。
根据您对问题的描述,我相信这就是您真正想要的(来自 GoButton
函数):
if (self.MainLabel != nil)
{
// get the first weather object in the 'weatherData's weather array, and
// use the description parsed from the json and saved in the 'myDescription'
// property here...
if let gmain = weatherData.weather?.first?.myDescription {
print(gmain)
DispatchQueue.main.async {
self.MainLabel.text! = String (describing: gmain)
}
}
}
我在 Swift 中为 iOS 制作了一个天气应用程序 4,我正在使用 OpenWeatherMap API 将 JSON 数据解析到应用程序,我有让大部分应用程序正常工作,用户输入一个城市,并显示天气。我有当前温度、当前风速、当前湿度,我正在尝试使当前描述正常工作,但无法显示。
我想让 MainLabel 显示当前的天气描述,但我无法让它工作。代码的顶部是来自 API 键的 JSON 数据,描述在天气部分。我试过 MainLabel.Weather?.Description 但它会打印出完整的描述、ID、Main 和 Icon 值。我将不胜感激。谢谢
这是我用来解码来自 OpenWeatherMap JSON 数据的结构 API:
JSON 结构如下:
import UIKit
//Below is the JSON data from the OpenWeatherMap API
struct Coordinate : Decodable {
let lat, lon : Double?
}
struct Weather : Decodable {
var id : Int?
var main, myDescription, icon : String?
enum CodingKeys : String, CodingKey {
case id = "id"
case main = "main"
case icon = "icon"
case myDescription = "description"
}
}
struct Sys : Decodable {
let type, id : Int?
let sunrise, sunset : Date?
let message : Double?
let country : String?
}
struct Main : Decodable {
let temp, tempMin, tempMax : Double?
let pressure, humidity : Int?
}
struct Wind : Decodable {
let speed : Double?
let deg : Int?
}
struct MyWeather : Decodable {
let coord : Coordinate?
let cod, visibility, id : Int?
let name : String?
let base : String?
let weather : [Weather]?
let sys : Sys?
let main : Main?
let wind : Wind?
let dt : Date?
}
查看下面的控制器:
class ViewController: UIViewController {
@IBOutlet weak var HumidityLabel: UILabel!
@IBOutlet weak var MainLabel: UILabel!
@IBOutlet weak var WindLabel: UILabel!
@IBOutlet weak var TempLabel: UILabel!
@IBOutlet weak var LocationLabel: UILabel!
//
@IBOutlet weak var userValue: UITextField!
//Assigning Labels
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
@IBAction func GoButton(_ sender: Any) {
let text: String = userValue.text!
guard let APIUrl = URL(string: "https://api.openweathermap.org/data/2.5/weather?q=" + text + "&appid=*********APIKEY*********&units=Metric") else { return }
//API KEY
URLSession.shared.dataTask(with: APIUrl) { data, response, error in
guard let data = data else { return }
let decoder = JSONDecoder()
//Decoder
do {
let weatherData = try decoder.decode(MyWeather.self, from: data)
if (self.MainLabel != nil)
{
if let gmain = weatherData.weather?.description {
print(gmain)
DispatchQueue.main.async {
self.MainLabel.text! = String (describing: gmain)
}
}
}
if (self.LocationLabel != nil)
{
if let gmain = weatherData.name {
print(gmain)
DispatchQueue.main.async {
self.LocationLabel.text! = "Current Weather in: " + String (gmain)
}
}
}
if (self.HumidityLabel != nil)
{
if let ghumidity = weatherData.main?.humidity
{
print(ghumidity, "THIS IS HUMIDITY")
DispatchQueue.main.async {
self.HumidityLabel.text! = String (ghumidity)
}
}
}
if (self.WindLabel != nil)
{
if let gspeed = weatherData.wind?.speed {
print(gspeed, "THIS IS THE SPEED")
DispatchQueue.main.async {
self.WindLabel.text! = String(gspeed) + " mph"
}
}
}
if (self.TempLabel != nil)
{
if let ggtemp = weatherData.main?.temp {
print(ggtemp, "THIS IS THE TEMP")
DispatchQueue.main.async {
self.TempLabel.text! = String (ggtemp) + " c"
}
}
}
} catch {
print(error.localizedDescription)
}
}.resume()
}
}
通读您的视图控制器代码,您似乎正试图将 weatherData.weather.description
中的值加载到您的标签中,这将是 Weather
对象数组的描述,而不是实际的您从 JSON 响应中解析的值。
查看 Weather
对象,您正在将 JSON 响应中的 'description' 值解析为 myDescription
属性 Weather
对象,Weather
对象放置在 weatherData
对象的数组中。
因此您需要从数组中的对象中获取该值,而不是简单地打印包含 Weather
对象的数组描述。
根据您对问题的描述,我相信这就是您真正想要的(来自 GoButton
函数):
if (self.MainLabel != nil)
{
// get the first weather object in the 'weatherData's weather array, and
// use the description parsed from the json and saved in the 'myDescription'
// property here...
if let gmain = weatherData.weather?.first?.myDescription {
print(gmain)
DispatchQueue.main.async {
self.MainLabel.text! = String (describing: gmain)
}
}
}