php: 如何在没有内容的情况下隐藏列表项

php: How to hide a list item if there is no content

在 php 中,我显示了一个带有 3 个列表项作为选项卡的 ul。对于没有内容的标签,如何让它们不显示?

<div class="grid col-540 fit" id="tabs">
<ul>
    <li><a href="#tabs-1">Profile</a></li>
    <li><a href="#tabs-2">Project Experience</a></li>

    <?php if (!empty(get('bio_publications')) { ?>
    <li><a href="#tabs-3">Publications</a></li>
    <?php } ?><?php endif ?>

</ul>
<div class="profile" id="tabs-1">
    <h2>Profile</h2>
    <?php the_content( __( 'Read more &#8250;', 'responsive' ) ); ?>
</div>
<div class="project-experience" id="tabs-2">
    <h2>Project Experience</h2>
    <?php echo get('bio_project_experience'); ?>
</div>
<div class="publications" id="tabs-3">
    <h2>Publications</h2>
<?php echo get('bio_publications'); ?>
</div>
</div>

我以为我可以用 if 语句来完成,但它不起作用。此特定 ul 的出版物为空,因此不应显示该选项卡。

感谢您的帮助。

您确实需要 IF 条件,但您需要在代码中获取制表符值 'earlier' 来检查条件,如下所示:

<?php
//get your stuff
$content = get_the_content();
$bio_project_experience = get('bio_project_experience');
$bio_publications = get('bio_publications');
?>
<div class="grid col-540 fit" id="tabs">
    <ul>
        <?php if ($content): ?><li><a href="#tabs-1">Profile</a></li><?php endif; ?>

       <?php if ($bio_project_experience): ?><li><a href="#tabs-2">Project Experience</a></li><?php endif; ?>

    <?php if ($bio_publications): ?> <li><a href="#tabs-3">Publications</a></li><?php endif ?>

</ul>
<?php if ($content): ?>
    <div class="profile" id="tabs-1">
        <h2>Profile</h2>
        <?php the_content( __( 'Read more &#8250;', 'responsive' ) ); ?>
    </div>
<?php endif; ?>
<?php if ($bio_project_experience): ?>
    <div class="project-experience" id="tabs-2">
        <h2>Project Experience</h2>
        <?php echo get('bio_project_experience'); ?>
    </div>
<?php endif; ?>
<?php if ($bio_publications): ?>
    <div class="publications" id="tabs-3">
        <h2>Publications</h2>
        <?php echo get('bio_publications'); ?>
    </div>
<?php endif; ?>
</div>