"Faking" 来自 3 个表的 sub-table 个结果，在 SQL 中
"Faking" a sub-table of results from 3 tables, in SQL
如果我有 table 个案例：
CASE_NUMBER | CASE_ID | STATUS | SUBJECT |
----------------------------------------------------------------
3108 | 123456 | Closed_Billable | Something Interesting
3109 | 325124 | Closed_Billable | Broken printer
3110 | 432432 | Open_Assigned | Email not working
还有 table 次通话：
PARENT_ID | STATUS | DUR(H) | DUR(M) | SUBJECT
---------------------------------------------------------------
123456 | Held | 1 | 30 | Initial discussion
123456 | Cancelled | 0 | 0 | Walk user through
123456 | Held | 0 | 45 | Remote debug session
325124 | Held | 1 | 0 | Consultation
325124 | Held | 1 | 15 | Needs assessment
432432 | Held | 1 | 30 | Support call
还有 table 次会议：
PARENT_ID | STATUS | DUR(H) | DUR(M) | SUBJECT
-------------------------------------------------------
123456 | Held | 3 | 15 | On-site work
325124 | Held | 2 | 0 | Un-jam printer
432432 | Held | 1 | 0 | Reconnect network
如何使用这些参数执行 select（这显然不是工作代码）：
SELECT cases.case_number, cases.subject, calls.subject, meetings.subject
WHERE cases.status="Closed_Billable" AND (calls.status="Held" OR meetings.status="Held)
LEFT JOIN cases
ON cases.case_id = calls.parent_id
LEFT JOIN cases
ON cases.case_id = meetings.parent_id
并以 "faked" 嵌套 table 结束，例如：
CASE_NUMBER | CASE SUBJECT | # CALLS | # MEETINGS | CALL SUBJECT | MEETING SUBJECT | DURATION (H) | DURATION (M) | TOTAL
-----------------------------------------------------------------------------------------------------------------------------------------
3108 | Something Interesting | 2 | 1 | | | | | 5.5H
| | | | Initial Discussion | | 1 | 30 |
| | | | Remote Debug Session | | 0 | 45 |
| | | | | On-site work | 3 | 15 |
3109 | Broken printer | 2 | 1 | | | | | 4.25H
| | | | Consultation | | 1 | 0 |
| | | | Needs assessment | | 1 | 15 |
| | | | | Un-jam printer | 2 | 0 |
我已经尽我所能尝试了连接和子查询，但我得到了重复的条目 - 例如，案例中的每个会议将显示 3 次，在这种情况下每个呼叫一次。
我难住了！显然还有其他领域我在这里拉，做电话和会议的计数，以及它们持续时间的总和，但我很乐意只显示这样的 table/sub-table。
有可能吗？
谢谢，
大卫.
如果没有一些非常难看的 "wrapper" 查询，你无法真正获得这样的最终结果，例如：
SET @prevCaseNum := 'blahdyblahnowaythisshouldmatchanything';
SET @prevCaseSub := 'seeabovetonotmatchanything';
SELECT IF(@prevCaseNum = CASE_NUMBER, '', CASE_NUMBER) AS CASE_NUMBER
, IF(@prevCaseNum = CASE_NUMBER AND @prevCaseSubject = CASE_SUBJECT, '', CASE_SUBJECT) AS CASE_SUBJECT
, etc.....
, @prevCaseNum := CASE_NUMBER AS prevCaseNum
, @prevCaseSubject = CASE_SUBJECT AS prevCaseSub
, etc....
FROM ( [the real query] ORDER BY CASE_NUMBER, etc....) AS trq
;
然后用另一个 select 包装所有这些以去除 prevCase 字段。
即使这样仍然无法在 "upper right".
上为您提供所需的空白
以您想要的确切格式组装查询结果..有点痛苦。可以做到，但是像这样的展示内容最好留给应用程序。
就是说，这会做你想做的事：
select case when case_id > floor(case_id) then ''
else case_number
end case_number,
coalesce(q1.c, '') calls,
coalesce(q2.c, '') meetings,
coalesce(calls.subject, '') `call subject`,
coalesce(meetings.subject, '') `meeting subject`,
case when calls.subject is not null then calls.dhour
when meetings.subject is not null then meetings.dhour
else ''
end dhour,
case when calls.subject is not null then calls.dmin
when meetings.subject is not null then meetings.dmin
else ''
end dhour,
coalesce(q3.total, '') total
from
(
select case_number, case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(case_id, '.1')
from cases where status = 'Closed_Billable'
union select case_number, concat(case_id, '.2')
from cases where status = 'Closed_Billable'
) main
left join
(select parent_id, count(*) c
from calls
where status != 'Cancelled'
group by parent_id ) q1
on q1.parent_id = case_id
left join
(select parent_id, count(*) c
from meetings
group by parent_id) q2
on q2.parent_id = case_id
left join
(select parent_id, sum(dhour + m) total
from
(select parent_id, dhour, dmin / 60 m
from calls
where status != 'Cancelled'
union all
select parent_id, dhour, dmin / 60 m
from meetings
) qq
group by parent_id
) q3
on q3.parent_id = case_id
left join calls
on concat(calls.parent_id, '.1') = main.case_id
left join meetings
on concat(meetings.parent_id, '.2') = main.case_id
order by case_id asc
请注意，我已重命名您的持续时间字段，因为我不喜欢其中的括号。
我们必须在查询中稍微修改 case_id 以便能够为您提供空白行/字段 - 这些都是使查询变得麻烦的原因
这里有一个演示：http://sqlfiddle.com/#!9/d59d4/21
编辑代码以在评论中使用不同的架构 fiddle
select case when case_id > floor(case_id) then ''
else case_number
end case_number,
coalesce(q1.c, '') calls,
coalesce(q2.c, '') meetings,
coalesce(calls.name, '') `call subject`,
coalesce(meetings.name, '') `meeting subject`,
case when calls.name is not null then calls.duration_hours
when meetings.name is not null then meetings.duration_hours
else ''
end duration_hours,
case when calls.name is not null then calls.duration_minutes
when meetings.name is not null then meetings.duration_minutes
else ''
end duration_hours,
coalesce(q3.total, '') total
from
(
select case_number, id as case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(id, '.1') as case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(id, '.2') as case_id
from cases where status = 'Closed_Billable'
) main
left join
(select parent_id, count(*) c
from calls
where status != 'Cancelled'
group by parent_id ) q1
on q1.parent_id = case_id
left join
(select parent_id, count(*) c
from meetings
group by parent_id) q2
on q2.parent_id = case_id
left join
(select parent_id, sum(duration_hours + m) total
from
(select parent_id, duration_hours, duration_minutes / 60 m
from calls
where status != 'Cancelled'
union all
select parent_id, duration_hours, duration_minutes / 60 m
from meetings
) qq
group by parent_id
) q3
on q3.parent_id = case_id
left join calls
on concat(calls.parent_id, '.1') = main.case_id
left join meetings
on concat(meetings.parent_id, '.2') = main.case_id
order by case_id asc
如果我有 table 个案例：
CASE_NUMBER | CASE_ID | STATUS | SUBJECT |
----------------------------------------------------------------
3108 | 123456 | Closed_Billable | Something Interesting
3109 | 325124 | Closed_Billable | Broken printer
3110 | 432432 | Open_Assigned | Email not working
还有 table 次通话：
PARENT_ID | STATUS | DUR(H) | DUR(M) | SUBJECT
---------------------------------------------------------------
123456 | Held | 1 | 30 | Initial discussion
123456 | Cancelled | 0 | 0 | Walk user through
123456 | Held | 0 | 45 | Remote debug session
325124 | Held | 1 | 0 | Consultation
325124 | Held | 1 | 15 | Needs assessment
432432 | Held | 1 | 30 | Support call
还有 table 次会议：
PARENT_ID | STATUS | DUR(H) | DUR(M) | SUBJECT
-------------------------------------------------------
123456 | Held | 3 | 15 | On-site work
325124 | Held | 2 | 0 | Un-jam printer
432432 | Held | 1 | 0 | Reconnect network
如何使用这些参数执行 select（这显然不是工作代码）：
SELECT cases.case_number, cases.subject, calls.subject, meetings.subject
WHERE cases.status="Closed_Billable" AND (calls.status="Held" OR meetings.status="Held)
LEFT JOIN cases
ON cases.case_id = calls.parent_id
LEFT JOIN cases
ON cases.case_id = meetings.parent_id
并以 "faked" 嵌套 table 结束，例如：
CASE_NUMBER | CASE SUBJECT | # CALLS | # MEETINGS | CALL SUBJECT | MEETING SUBJECT | DURATION (H) | DURATION (M) | TOTAL
-----------------------------------------------------------------------------------------------------------------------------------------
3108 | Something Interesting | 2 | 1 | | | | | 5.5H
| | | | Initial Discussion | | 1 | 30 |
| | | | Remote Debug Session | | 0 | 45 |
| | | | | On-site work | 3 | 15 |
3109 | Broken printer | 2 | 1 | | | | | 4.25H
| | | | Consultation | | 1 | 0 |
| | | | Needs assessment | | 1 | 15 |
| | | | | Un-jam printer | 2 | 0 |
我已经尽我所能尝试了连接和子查询，但我得到了重复的条目 - 例如，案例中的每个会议将显示 3 次，在这种情况下每个呼叫一次。
我难住了！显然还有其他领域我在这里拉，做电话和会议的计数，以及它们持续时间的总和，但我很乐意只显示这样的 table/sub-table。
有可能吗？
谢谢， 大卫.
如果没有一些非常难看的 "wrapper" 查询，你无法真正获得这样的最终结果，例如：
SET @prevCaseNum := 'blahdyblahnowaythisshouldmatchanything';
SET @prevCaseSub := 'seeabovetonotmatchanything';
SELECT IF(@prevCaseNum = CASE_NUMBER, '', CASE_NUMBER) AS CASE_NUMBER
, IF(@prevCaseNum = CASE_NUMBER AND @prevCaseSubject = CASE_SUBJECT, '', CASE_SUBJECT) AS CASE_SUBJECT
, etc.....
, @prevCaseNum := CASE_NUMBER AS prevCaseNum
, @prevCaseSubject = CASE_SUBJECT AS prevCaseSub
, etc....
FROM ( [the real query] ORDER BY CASE_NUMBER, etc....) AS trq
;
然后用另一个 select 包装所有这些以去除 prevCase 字段。 即使这样仍然无法在 "upper right".
上为您提供所需的空白以您想要的确切格式组装查询结果..有点痛苦。可以做到，但是像这样的展示内容最好留给应用程序。
就是说，这会做你想做的事：
select case when case_id > floor(case_id) then ''
else case_number
end case_number,
coalesce(q1.c, '') calls,
coalesce(q2.c, '') meetings,
coalesce(calls.subject, '') `call subject`,
coalesce(meetings.subject, '') `meeting subject`,
case when calls.subject is not null then calls.dhour
when meetings.subject is not null then meetings.dhour
else ''
end dhour,
case when calls.subject is not null then calls.dmin
when meetings.subject is not null then meetings.dmin
else ''
end dhour,
coalesce(q3.total, '') total
from
(
select case_number, case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(case_id, '.1')
from cases where status = 'Closed_Billable'
union select case_number, concat(case_id, '.2')
from cases where status = 'Closed_Billable'
) main
left join
(select parent_id, count(*) c
from calls
where status != 'Cancelled'
group by parent_id ) q1
on q1.parent_id = case_id
left join
(select parent_id, count(*) c
from meetings
group by parent_id) q2
on q2.parent_id = case_id
left join
(select parent_id, sum(dhour + m) total
from
(select parent_id, dhour, dmin / 60 m
from calls
where status != 'Cancelled'
union all
select parent_id, dhour, dmin / 60 m
from meetings
) qq
group by parent_id
) q3
on q3.parent_id = case_id
left join calls
on concat(calls.parent_id, '.1') = main.case_id
left join meetings
on concat(meetings.parent_id, '.2') = main.case_id
order by case_id asc
请注意，我已重命名您的持续时间字段，因为我不喜欢其中的括号。
我们必须在查询中稍微修改 case_id 以便能够为您提供空白行/字段 - 这些都是使查询变得麻烦的原因
这里有一个演示：http://sqlfiddle.com/#!9/d59d4/21
编辑代码以在评论中使用不同的架构 fiddle
select case when case_id > floor(case_id) then ''
else case_number
end case_number,
coalesce(q1.c, '') calls,
coalesce(q2.c, '') meetings,
coalesce(calls.name, '') `call subject`,
coalesce(meetings.name, '') `meeting subject`,
case when calls.name is not null then calls.duration_hours
when meetings.name is not null then meetings.duration_hours
else ''
end duration_hours,
case when calls.name is not null then calls.duration_minutes
when meetings.name is not null then meetings.duration_minutes
else ''
end duration_hours,
coalesce(q3.total, '') total
from
(
select case_number, id as case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(id, '.1') as case_id
from cases where status = 'Closed_Billable'
union select case_number, concat(id, '.2') as case_id
from cases where status = 'Closed_Billable'
) main
left join
(select parent_id, count(*) c
from calls
where status != 'Cancelled'
group by parent_id ) q1
on q1.parent_id = case_id
left join
(select parent_id, count(*) c
from meetings
group by parent_id) q2
on q2.parent_id = case_id
left join
(select parent_id, sum(duration_hours + m) total
from
(select parent_id, duration_hours, duration_minutes / 60 m
from calls
where status != 'Cancelled'
union all
select parent_id, duration_hours, duration_minutes / 60 m
from meetings
) qq
group by parent_id
) q3
on q3.parent_id = case_id
left join calls
on concat(calls.parent_id, '.1') = main.case_id
left join meetings
on concat(meetings.parent_id, '.2') = main.case_id
order by case_id asc