从 Buffer node.js 前面删除元素

Question

我知道有一个名为 slice() 的函数，但我正在寻找 splice()，但该函数不存在，我该如何以其他方式实现它？

var buffer = new Buffer("090001060001020304090000060001020304", "hex");
var packetLength = buffer.readUInt16LE(0)
console.log('before slice buffer = ' + buffer.toString('hex'))
buffer = buffer.slice(0, packetLength)
console.log('after slice buffer = ' + buffer.toString('hex'))

我得到的输出是

before slice buffer = 090001060001020304090000060001020304
after slice buffer = 090001060001020304

但我需要

before slice buffer = 090001060001020304090000060001020304
after slice buffer = 090000060001020304

前面的 9 个字节应该被删除，后面的字节应该被移到前面我该如何做这个简单的方法？

Answer 1

解决了..

console.log('before slice buffer = ' + buffer.toString('hex'))
var newBuffer = new Buffer(buffer.length - packetLength);
buffer.copy(newBuffer, 0, packetLength, packetLength + buffer.length);
console.log('after slice buffer =  ' + newBuffer.toString('hex'))

before slice buffer = 090001060001020304090000060001020304
after slice buffer =  090000060001020304

Answer 2

只需将缓冲区的起点更改为偏移 9，而不是从 0 开始

let newBuffer = buffer.slice(9).toString('hex')

从 Buffer node.js 前面删除元素

remove elements from front of Buffer node.js

buffer

slice

splice

node.js

array-splice