类型 'number' 不可分配给类型 'string'

Question

我有这样一个错误：

Type 'number' is not assignable to type 'string'.

此处错误：

swal.getContent().querySelector('strong').textContent = swal.getTimerLeft()

我该如何解决？

完整代码：

    let timerInterval
    swal({
      title: 'Auto close alert!',
      html: 'I will close in <strong></strong> seconds.',
      timer: 2000,
      onOpen: () => {
        swal.showLoading()
        timerInterval = setInterval(() => {
          swal.getContent().querySelector('strong')
            .textContent = swal.getTimerLeft()
        }, 100)
      },
      onClose: () => {
        clearInterval(timerInterval)
      }
    }).then((result) => {
      if (
        // Read more about handling dismissals
        result.dismiss === swal.DismissReason.timer
      ) {
        console.log('I was closed by the timer')
      }
    })

Answer 1

Node.textContent 是一个字符串，swal.getTimerLeft() 不是 return 一个字符串。

要解决此问题，请使用 Number.prototype.toString():

Swal.getHtmlContainer().querySelector('strong').textContent = swal.getTimerLeft().toString();

类型 'number' 不可分配给类型 'string'

Type 'number' is not assignable to type 'string'

angular

sweetalert2