使用 group by condition 使结果唯一

Question

这里我想加入两个 table 并想产生类似

的输出

Akbar Travels building      2018-10
Thrikandiyur Quarters       2018-10


Akbar Travels building     2018-11
Thrikandiyur Quarters      2018-11

这里我有两个 table 的名字 table A,table B,table A 结构看起来像这样

 category_id           category_name    
    5               Akbar Travels building          
    6               Thrikandiyur Quarters

table B 结构如下

id   paying_date   paying_month     parent_category     
1    2018-10-01      2018-10            5   
2    2018-10-01      2018-10            5   
3    2018-10-01      2018-11            5   
4    2018-11-01      2018-11            5   
5    2018-10-01      2018-10            6
6    2018-10-10      2018-12            5

这里为了获取输出我写了这样的代码代码

public function get_date_wise_pdf_report($from, $to)
{
       $query=$this->db->query("SELECT distinct A.category_name,B.paying_month from tableA A left join tableB B  on A.category_id = B.parent_category and B.paying_date BETWEEN '{$from}' AND '{$to}' order by B.paying_month");
       return $query->result();
 }

但是当我使用它时，我会变成这样

Akbar Travels building     2018-10
Thrikandiyur Quarters      2018-10
Akbar Travels building     2018-10
Thrikandiyur Quarters      2018-10

这里无法给group by语句，如果我只给两行就出来了，请帮我解决

Answer 1

尝试使用子查询

demo

 select distinct catname,paymon
from
(SELECT A.catname,DATE_FORMAT(B.paydate, "%Y-%m") as paymon from  A 
left join  B  on A.catid = B.parentcatid and B.paydate BETWEEN '2018-10-01' AND '2018-12-31'
)X order by paymon

使用 group by condition 使结果唯一

make results unique by using group by condition

php

mysql

join

group-by

distinct