输出目录下所有包含一系列正则表达式-python的txt文件

Question

因此，我正在尝试输出我的目录中包含多个正则表达式中的任何一个的所有文本文件。

这是一个在文件中搜索 Phone 数字的示例正则表达式

#Search for Phone Numbers
regex2 =r'\d\d\d[-]\d\d\d[-]\d\d\d\d'

这是我获取所有文件的代码，但我对将正则表达式放在何处感到困惑。

import glob

folder_path = "C:\Temp"
file_pattern = "\*.txt"
search_string = "hello"

match_list = []

folder_contents = glob.glob(folder_path + file_pattern)

for file in folder_contents:
    print("Checking", file)
    read_file = open(file, 'rt').read()

    if search_string in read_file:
        match_list.append(file)

print("Files containing search string")
for file in match_list:
    print(file)

这是编译我目录中所有 txt 文件的另一种方法：

import glob
import errno
path = '/home//*.txt' #note C:
files = glob.glob(path)
for name in files:
    with open(name) as f:
        for line in f:
            split = line.split()
            if split:
                print(line.split())

我尝试将我的正则表达式放在上述每个语句的 if 语句中，但出现错误。有什么想法吗？

Answer 1

import re

# Define your regex
regex2 = re.compile(r'\d\d\d[-]\d\d\d[-]\d\d\d\d')

# Read files...

# Check if we have matches in the file content
matches = regex2.findall(read_file)
if matches:
    match_list.append(file)
    print('file:', file)
    print('matches:', matches)

输出目录下所有包含一系列正则表达式-python的txt文件

Output all txt files in directory that contains a series of regular expression-python

python

glob