如何在父 Xpath Class 中排除 Class？ PHP

Question

把我逼上墙是这样的DOM

<div class="product-intro"><p class="product-desc"><span class="product-model">234</span>Product Description</p></div>

不是这样的...参数无效，未找到节点：

$node3 = $xp->query("//p[@class='product-desc and not(@class='product-model']");
$node3 = $xp->query("//p[@class='product-desc'][not([@class='product-model'])]");

仅此一项：

$node3 = $xp->query("//p[@class='product-desc']");

就获得结果而言，效果非常好。输出是

234Product Description

我知道我可以做一个字符串替换，但不是很理想。我如何让它在我的查询中排除 product-model class？

整个脚本：

$x = '<div class="product-item productContainer" data-itemno="234">
    <div class="product-and-intro">
        <div class="product">
            <a href="/en/234.html" title="Product Description"> 
                <img src="/ProductImages/106/234.jpg" alt="Product Description" class="itemImage" />
                <div class="product-intro">
                    <p class="product-desc"><span class="product-model">234</span>Product Description</p>
                    <p class="price"><span class="us">US$</span>6.50 <span class="oldprice"><s>$ 13.00</s></span></p>
                </div>
            </a>
        </div>
    </div>
</div>';



$dom = new DOMDocument();
libxml_use_internal_errors(true);
$dom->loadHTML($x);
$xp = new DOMXPath($dom);
$node1 = $xp->query("//div[@class='product']//img");
$node2 = $xp->query("//span[@class='product-model']");
$node3 = $xp->query("//p[@class='product-desc']");
// $node3 = $xp->query("//p[@class='product-desc']/text()[2]");
// $node3 = $xp->query("//p[@class='product-desc' and not(span/@class='product-model')]");
$node4 = $xp->query("//p[@class='price']");

foreach ($node1 as $n) {
    echo $n->getAttribute('src');
    echo '<br>';
}

foreach ($node2 as $n2) {
    echo $n2->nodeValue;
        echo '<br>';
}

foreach ($node3 as $n3) {
    echo $n3->nodeValue;
        echo '<br>';
}

foreach ($node4 as $n4) {
    echo $n4->nodeValue;
        echo '<br>';
}

Answer 1

如果你想select所有@class属性值为product-desc的元素，然后过滤掉那些有span子元素的元素- 具有 @class 属性值的元素 product-model 您可以使用此 XPath 表达式：

//p[@class='product-desc' and not(span/@class='product-model')]

或者，整体

$node3 = $xp->query("//p[@class='product-desc' and not(span/@class='product-model')]");

如何在父 Xpath Class 中排除 Class？ PHP

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php

xpath

dom

domdocument