json 数据通过变量传递时，CURL 未返回正确的响应

Question

$data 是保存 json 字符串的变量 {"clientId":"MyClientID","clientSecret":"MyClientSecret","script":"<?php\n echo \"Welcome to GLB Coding Club\";\n?>\n","stdin":"","language":"php","versionIndex":"2"}.

正如您在下面第一行中看到的那样。我使用 json_encode()

将数组编码为 json

$data = json_encode(array("clientId"=>"MyClientID","clientSecret"=>"MyClientSecret","script"=> $this->input->post("script",true),"stdin"=>$this->input->post("stdin",true),"language"=>$this->input->post("language",true),"versionIndex"=>$this->input->post("versionIndex",true)));

        $curl = curl_init();
        curl_setopt_array($curl, array(
            CURLOPT_URL => "https://api.jdoodle.com/v1/execute",
            CURLOPT_RETURNTRANSFER => true,
            CURLOPT_ENCODING => "",
            CURLOPT_MAXREDIRS => 10,
            CURLOPT_TIMEOUT => 30,
            CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
            CURLOPT_CUSTOMREQUEST => "POST",
            CURLOPT_POSTFIELDS => $data,
            CURLOPT_HTTPHEADER => array("cache-control: no-cache","content-type: application/json"),
            CURLOPT_SSL_VERIFYPEER => false
        ));

        $response = curl_exec($curl);
        $err = curl_error($curl);
        curl_close($curl);

        if ($err) {
            echo "cURL Error #:" . $err;
        } 
        else {
            echo $response;
        }

jdoodle 没有返回正确的 $response，而是返回要执行的语句。但是，如果我将 $data 替换为 CURLOPT_POSTFIELDS => $data 处的实际 json 字符串 {"clientId":"MyClientID","clientSecret":"MyClientSecret","script":"<?php\n echo \"Welcome to GLB Coding Club\";\n?>\n","stdin":"","language":"php","versionIndex":"2"}，则 jdoodle 将返回正确的 $response.

Answer 1

那么，干脆

json_encode(array("clientId"=>"MyClientID","clientSecret"=>"MyClientSecret","script"=> $this->input->post("script",true),"stdin"=>$this->input->post("stdin",true),"language"=>$this->input->post("language",true),"versionIndex"=>$this->input->post("versionIndex",true)))

没有生成您期望的 $data 字符串并给出正确的响应：

'{"clientId":"MyClientID","clientSecret":"MyClientSecret","script":"<?php\n echo \"Welcome to GLB Coding Club\";\n?>\n","stdin":"","language":"php","versionIndex":"2"}'

刚刚

echo $data;
exit(0);

在第一行之后检查形成 $data 字符串时有什么问题

Answer 2

我只是将 $this->input->post("script",true) 编辑为 html_entity_decode($this->input->post("script",true))。

json 数据通过变量传递时，CURL 未返回正确的响应

CURL is not returning correct response when json data is passed through variable

php-curl

jdoodle