在 jbuider 中显示之前检查散列值，Ruby on Rails

Question

我有一个 jbuilder 来显示我的对象。

这就是它的样子（部分）

o = @property_object

json.features o.property_object_feature_pack, :pool, :garage, terrace

接下来显示的是：

{
 features: {
  pool: {
   params: null,
   present: "false"
   },
  garage_parking: {
   params: null,
   present: "false"
   },
  terrace_balcony: {
   params: null,
   present: "true"
   }
 }
}

问题是我不想在 present: "false" 的输出特征中显示。为了解决这个问题，我编写了下一个代码

json.features o.property_object_feature_pack, :pool if o.property_object_feature_pack.pool['present'] === "true"
json.features o.property_object_feature_pack, :garage_parking if o.property_object_feature_pack.garage_parking['present'] === "true"
json.features o.property_object_feature_pack, :terrace_balcony if o.property_object_feature_pack.terrace_balcony['present'] === "true"

它有效 - 但看起来很糟糕。如何重构？

下一个问题，可能是以后ActiveRecord要加入的新特性，我想知道我们可以迭代o.property_object_feature_pack不设置名称吗？ (:pool, :garage_parking 等..)

ps. 原始 o.property_object_feature_pack

features: {
 id: 820,
 property_object_id: 56879,
 created_at: "2015-04-27T18:25:25.712Z",
 updated_at: "2015-04-27T18:25:25.712Z",
 pool: {
  params: null,
  present: "false"
 },
 garage_parking: {
  params: null,
  present: "false"
 },
 terrace_balcony: {
  params: null,
  present: "true"
 },
 av_apartments: {
  params: null,
  present: "false"
 }
}

已更新

受到#mudasobwa 的启发，我创建了一个小帮助方法来解决我的问题

def features_list
    @property_object.property_object_feature_pack.as_json.select! do |_, v|
      v.is_a?(Hash) && v['present'] == 'true'
    end
  end

Answer 1

我不知道 jbuilder 是什么，但我建议将 json 转换为纯 ruby 散列，随心所欲，然后将其转换回 json:

require 'json'
hash = JSON.parse what_you_got_from_builder
hash[:features].select! do |_, v| 
  !v.is_a?(Hash) || v[:present] == 'true' 
end
hash.to_json

在 jbuider 中显示之前检查散列值，Ruby on Rails

Checking values of hash before show in jbuider , Ruby on Rails

ruby

ruby-on-rails

jbuilder