如何获取列表中的索引

Question

我如何检查是否找到该值并打印语法？我已经完成了所有代码，但我的问题是我需要找到值在列表中的位置。问题出在代码的末尾。我在那些地方放了#blank，因为我不知道该放什么。

这是我的代码：

list_of_scores = []

count = 0

for i in range(10):

    grade = int(input("Enter a quiz score "))
    list_of_scores.append(grade)

for grade in list_of_scores:

    while(count < 10):
        print("The score at position[", count, "] = ", list_of_scores[count])
        count = count + 1

search_value = (int(input("Enter a number to search for: ")))

***下面是我遇到问题的地方。我的代码的顶部应该是这样的：

while(count < len(list_of_scores)):
    if(search_value) in list_of_scores:
        print("The value of ", search_value, "is in the list at index",#blank)
    else:
        if search_value not in list_of_scores:
            print(input("Sorry, this value isn't found. Please enter a new number:"))

print("The location of this value is: ", list_of_scores)

Answer 1

使用index()获取列表中项目的索引

print("The value of ", search_value, "is in the list at index",list_of_scores.index(search_value))

如何获取列表中的索引

How to get index in list

python

python-3.7