Java - Thymeleaf - 如何在 TemplateEngine 中处理 InputStream? (独立模板)
Java - Thymeleaf - How to process an InputStream in TemplateEngine ? (Stand-alone Templating)
我面临这样一种情况,我需要处理一个 HTML 模板 (index.html),该模板是通过 Thymeleaf TemplateEngine 和我的数据 POJO 从 ZIP 文件(通过 ZipInputStream)解压缩的。
所以我现在拥有的是解压后的模板文件的 InputStream。
我相信TemplateResolver会帮助我解决这个问题。
TemplateResolver 是一个通用实现,允许您指定自己的 IResourceResolver 实现,以您需要的任何方式获取输入流。您可以创建自己的资源解析器(实现 IResourceResolver)并将其设置为 TemplateResolver 实例。
如何完成这个任务?有什么见解吗?
// index.html is the byte[] here, 'resourceData'
InputStream fileinputStream = new ByteArrayInputStream(resourceData);
FileResourceResolver fileResourceResolver = new FileResourceResolver();
TemplateResolver resolver = new TemplateResolver();
resolver.setTemplateMode("XHTML");
resolver.setSuffix(".html");
resolver.setResourceResolver(fileResourceResolver);
TemplateEngine engine = new TemplateEngine();
engine.setTemplateResolver(resolver);
Context context = new Context(Locale.US);
context.setVariable("data", myDataPojo);
return engine.process("index", context);
我找到了方法:)希望遇到同样问题的任何人都可以使用这个解决方案。
private static class CustomTemplateResolver implements IResourceResolver {
private InputStream inputStream;
private String templateName;
public CustomTemplateResolver(String templateName, InputStream inputStream) {
this.templateName = templateName;
this.inputStream = inputStream;
}
@Override
public String getName() {
return templateName;
}
@Override
public InputStream getResourceAsStream(TemplateProcessingParameters templateProcessingParameters, String resourceName) {
return inputStream;
}
}
测试Class
@Test
public void createPdfFromZip() throws Exception {
String fileBundleZipFile = "sample.zip";
String templateFileName = "index";
String fileExt = ".html";
ClassPathResource resourceZip = new ClassPathResource(fileBundleZipFile);
ZipFile zipFile = new ZipFile(new File(this.getClass().getResource("/" + fileBundleZipFile).getFile()));
ZipInputStream zipInputStream = new ZipInputStream(resourceZip.getInputStream());
ZipEntry zipEntry = zipInputStream.getNextEntry();
while (zipEntry != null) {
if (zipEntry.getName().equals(templateFileName + fileExt)) {
TemplateResolver resolver = new TemplateResolver();
resolver.setTemplateMode("XHTML");
resolver.setSuffix(fileExt);
resolver.setResourceResolver(new CustomTemplateResolver(templateFileName, zipFile.getInputStream(zipEntry)));
MyPojo data= getData();
TemplateEngine engine = new TemplateEngine();
engine.setTemplateResolver(resolver);
Context context = new Context(Locale.US);
context.setVariable("data", data);
String dataHTMLString = engine.process(templateFileName, context);
Path tempFile = Files.createTempFile("unzipped-data-html", ".pdf");
createDataPdfWithCss(tempFile, dataHTMLString);
}
zipEntry = zipInputStream.getNextEntry();
}
zipInputStream.closeEntry();
zipInputStream.close();
}
我面临这样一种情况,我需要处理一个 HTML 模板 (index.html),该模板是通过 Thymeleaf TemplateEngine 和我的数据 POJO 从 ZIP 文件(通过 ZipInputStream)解压缩的。 所以我现在拥有的是解压后的模板文件的 InputStream。 我相信TemplateResolver会帮助我解决这个问题。
TemplateResolver 是一个通用实现,允许您指定自己的 IResourceResolver 实现,以您需要的任何方式获取输入流。您可以创建自己的资源解析器(实现 IResourceResolver)并将其设置为 TemplateResolver 实例。
如何完成这个任务?有什么见解吗?
// index.html is the byte[] here, 'resourceData'
InputStream fileinputStream = new ByteArrayInputStream(resourceData);
FileResourceResolver fileResourceResolver = new FileResourceResolver();
TemplateResolver resolver = new TemplateResolver();
resolver.setTemplateMode("XHTML");
resolver.setSuffix(".html");
resolver.setResourceResolver(fileResourceResolver);
TemplateEngine engine = new TemplateEngine();
engine.setTemplateResolver(resolver);
Context context = new Context(Locale.US);
context.setVariable("data", myDataPojo);
return engine.process("index", context);
我找到了方法:)希望遇到同样问题的任何人都可以使用这个解决方案。
private static class CustomTemplateResolver implements IResourceResolver {
private InputStream inputStream;
private String templateName;
public CustomTemplateResolver(String templateName, InputStream inputStream) {
this.templateName = templateName;
this.inputStream = inputStream;
}
@Override
public String getName() {
return templateName;
}
@Override
public InputStream getResourceAsStream(TemplateProcessingParameters templateProcessingParameters, String resourceName) {
return inputStream;
}
}
测试Class
@Test
public void createPdfFromZip() throws Exception {
String fileBundleZipFile = "sample.zip";
String templateFileName = "index";
String fileExt = ".html";
ClassPathResource resourceZip = new ClassPathResource(fileBundleZipFile);
ZipFile zipFile = new ZipFile(new File(this.getClass().getResource("/" + fileBundleZipFile).getFile()));
ZipInputStream zipInputStream = new ZipInputStream(resourceZip.getInputStream());
ZipEntry zipEntry = zipInputStream.getNextEntry();
while (zipEntry != null) {
if (zipEntry.getName().equals(templateFileName + fileExt)) {
TemplateResolver resolver = new TemplateResolver();
resolver.setTemplateMode("XHTML");
resolver.setSuffix(fileExt);
resolver.setResourceResolver(new CustomTemplateResolver(templateFileName, zipFile.getInputStream(zipEntry)));
MyPojo data= getData();
TemplateEngine engine = new TemplateEngine();
engine.setTemplateResolver(resolver);
Context context = new Context(Locale.US);
context.setVariable("data", data);
String dataHTMLString = engine.process(templateFileName, context);
Path tempFile = Files.createTempFile("unzipped-data-html", ".pdf");
createDataPdfWithCss(tempFile, dataHTMLString);
}
zipEntry = zipInputStream.getNextEntry();
}
zipInputStream.closeEntry();
zipInputStream.close();
}