用中间线交换二维矩阵对角线
Swapping 2D matrix diagonal with a middle line
我有一个 Java 二维数组
String arraylist numberSeq[][];
数组列表里面有1到25的数字,
numberSeq[0][0] = 1, [0][1] = 2, [0][2] = 3 , [0][3] = 4 , [0][4] = 5
numberSeq[1][0] = 6, [1][1] = 7, [1][2] = 8 , [1][3] = 9 , [1][4] = 10
......
numberSeq[4][0] = 21,[4][1] = 22,[4][2] = 23, [4][3] = 24, [4][4] = 25
所以数字会像
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
进行对角线交换后,我希望输出像这样
25 20 15 10 5
24 19 14 9 4
23 18 13 8 3
22 17 12 7 2
21 16 11 6 1
当我只能声明一个局部变量时,如何实现这一点?
如果一个局部变量无法实现,我最少需要多少个局部变量?
这应该有所帮助。所以是的,可以使用单个局部变量进行交换。
public swapDiagonally(int[][] mtx) {
for(int i = 0 ;i< mtx.length; i++){
for(int j = 0; j < mtx[0].length - i; j++){
int temp = mtx[i][j];
mtx[j][i]; = mtx[mtx.length-1-i][mtx[0].length-1-j];
mtx[mtx.length-1-i][mtx[0].length-1-j] = temp;
}
}
}
我实际上是在遍历 'total rows - N' 每 N 列,因此,帮助我遍历这个结构:
1 2 3 4
1 2 3
1 2
1
对于 4x4 阵列!!!
以下循环将按照您的问题进行对角线交换:
int n=5;
int[][] newmat = new int[5][5];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
newmat[(n-1) - j][(n-1)- i] = matrix[i][j];
}
}
您可以通过制作另一个 teo 维数组,以正确的顺序遍历您的第一个数组并post它到一个新的数组来做到这一点。
public class MyClass {
public static void main(String args[]) {
int dimension = 5;
int[][] numberSeq = new int[dimension][dimension];
numberSeq[0][0] = 1; numberSeq[0][1] = 2;numberSeq[0][2] = 3;numberSeq[0][3] = 4;numberSeq[0][4] = 5;
numberSeq[1][0] = 6; numberSeq[1][1] = 7;numberSeq[1][2] = 8;numberSeq[1][3] = 9;numberSeq[1][4] = 10;
numberSeq[2][0] = 11;numberSeq[2][1] = 12;numberSeq[2][2] = 13;numberSeq[2][3] = 14;numberSeq[2][4] = 15;
numberSeq[3][0] = 16;numberSeq[3][1] = 17;numberSeq[3][2] = 18;numberSeq[3][3] = 19;numberSeq[3][4] = 20;
numberSeq[4][0] = 21;numberSeq[4][1] = 22;numberSeq[4][2] = 23;numberSeq[4][3] = 24;numberSeq[4][4] = 25;
int[][] flippedSeq = new int[dimension][dimension];
// This is the flipping part
for(int i = 0; i < dimension; i++)
{
for(int j = 0; j < dimension; j++)
{
flippedSeq[i][j] = numberSeq[dimension-1-j][dimension-1-i];
}
}
PrintMatrix(numberSeq);
System.out.println();
PrintMatrix(flippedSeq);
}
public static void PrintMatrix(int[][] mat)
{
for(int i = 0; i < mat.length; i++)
{
for(int j = 0; j < mat[i].length; j++)
System.out.print(mat[i][j] + " ");
System.out.println();
}
}
}
我希望这就是“1 个局部变量”的意思。
输出为:
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
25 20 15 10 5
24 19 14 9 4
23 18 13 8 3
22 17 12 7 2
21 16 11 6 1
我有一个 Java 二维数组
String arraylist numberSeq[][];
数组列表里面有1到25的数字,
numberSeq[0][0] = 1, [0][1] = 2, [0][2] = 3 , [0][3] = 4 , [0][4] = 5
numberSeq[1][0] = 6, [1][1] = 7, [1][2] = 8 , [1][3] = 9 , [1][4] = 10
......
numberSeq[4][0] = 21,[4][1] = 22,[4][2] = 23, [4][3] = 24, [4][4] = 25
所以数字会像
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
进行对角线交换后,我希望输出像这样
25 20 15 10 5
24 19 14 9 4
23 18 13 8 3
22 17 12 7 2
21 16 11 6 1
当我只能声明一个局部变量时,如何实现这一点?
如果一个局部变量无法实现,我最少需要多少个局部变量?
这应该有所帮助。所以是的,可以使用单个局部变量进行交换。
public swapDiagonally(int[][] mtx) {
for(int i = 0 ;i< mtx.length; i++){
for(int j = 0; j < mtx[0].length - i; j++){
int temp = mtx[i][j];
mtx[j][i]; = mtx[mtx.length-1-i][mtx[0].length-1-j];
mtx[mtx.length-1-i][mtx[0].length-1-j] = temp;
}
}
}
我实际上是在遍历 'total rows - N' 每 N 列,因此,帮助我遍历这个结构:
1 2 3 4
1 2 3
1 2
1
对于 4x4 阵列!!!
以下循环将按照您的问题进行对角线交换:
int n=5;
int[][] newmat = new int[5][5];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
newmat[(n-1) - j][(n-1)- i] = matrix[i][j];
}
}
您可以通过制作另一个 teo 维数组,以正确的顺序遍历您的第一个数组并post它到一个新的数组来做到这一点。
public class MyClass {
public static void main(String args[]) {
int dimension = 5;
int[][] numberSeq = new int[dimension][dimension];
numberSeq[0][0] = 1; numberSeq[0][1] = 2;numberSeq[0][2] = 3;numberSeq[0][3] = 4;numberSeq[0][4] = 5;
numberSeq[1][0] = 6; numberSeq[1][1] = 7;numberSeq[1][2] = 8;numberSeq[1][3] = 9;numberSeq[1][4] = 10;
numberSeq[2][0] = 11;numberSeq[2][1] = 12;numberSeq[2][2] = 13;numberSeq[2][3] = 14;numberSeq[2][4] = 15;
numberSeq[3][0] = 16;numberSeq[3][1] = 17;numberSeq[3][2] = 18;numberSeq[3][3] = 19;numberSeq[3][4] = 20;
numberSeq[4][0] = 21;numberSeq[4][1] = 22;numberSeq[4][2] = 23;numberSeq[4][3] = 24;numberSeq[4][4] = 25;
int[][] flippedSeq = new int[dimension][dimension];
// This is the flipping part
for(int i = 0; i < dimension; i++)
{
for(int j = 0; j < dimension; j++)
{
flippedSeq[i][j] = numberSeq[dimension-1-j][dimension-1-i];
}
}
PrintMatrix(numberSeq);
System.out.println();
PrintMatrix(flippedSeq);
}
public static void PrintMatrix(int[][] mat)
{
for(int i = 0; i < mat.length; i++)
{
for(int j = 0; j < mat[i].length; j++)
System.out.print(mat[i][j] + " ");
System.out.println();
}
}
}
我希望这就是“1 个局部变量”的意思。
输出为:
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
25 20 15 10 5
24 19 14 9 4
23 18 13 8 3
22 17 12 7 2
21 16 11 6 1