如何启动 WindowsInternal.ComposableShell.Experiences.TextInput.InputApp

Question

我想在 C:\Windows\SystemApps\InputApp_cw5n1h2txyewy 启动 WindowsInternal.ComposableShell.Experiences.TextInput.InputApp。明确地说，我不想显示触摸键盘，我只需要这个特定的过程是运行。有没有办法做到这一点？使用 .NET 扩展是可以接受的，但不是首选。

我想执行此操作以在启动时添加一个 StateChangedWatcher，但该进程在启动时尚不存在，需要手动启动才能立即运行。此外，手动将其添加到启动不会启动它，也不会简单地尝试执行它。是否需要启动任何参数？

Answer 1

To be clear, I don't want to display the touch-keyboard, I just need this particular process to be running. Is there a way to achieve that?

您会在 C:\Windows\SystemApps\InputApp_cw5n1h2txyewy 文件夹中找到 AppxManifest.xml。里面有 windows.protocol 个名字。换句话说，您可以使用 Windows.System.Launcher

启动它

<uap:Extension Category="windows.protocol">
  <uap:Protocol Name="ms-inputapp" DesiredView="useMinimum">
    <uap:DisplayName>Input App</uap:DisplayName>
  </uap:Protocol>
</uap:Extension>

用法

private async void Button_Click(object sender, RoutedEventArgs e)
{
    var options = new Windows.System.LauncherOptions();
    options.DesiredRemainingView = Windows.UI.ViewManagement.ViewSizePreference.UseMinimum;
    var success = await Windows.System.Launcher.LaunchUriAsync(new Uri("ms-inputapp:"), options);
}

如何启动 WindowsInternal.ComposableShell.Experiences.TextInput.InputApp

How to launch WindowsInternal.ComposableShell.Experiences.TextInput.InputApp

c#

uwp

desktop-bridge