symfony 在表单中注入参数
symfony4 inject parameter in form
我有一个业务实体和一个 BusinessObject 实体,我想在创建新的 BusinessObject 时将 BusinessObject link 到当前业务。
例如,如果我的路线是 business/{id}/object/new
,我希望对象与业务相关(感谢 id)。
在我的 BusinessObject 控制器中,我设法使用 @ParamConverter
来获取业务 ID。
在我的 BusinessObject 表单中,我将 HiddenType 放入我的业务条目中,因为我不希望它出现,并将 data
设置为 business_ID。
我在 configureOptions 中挣扎以获取业务 ID,我不知道如何从这里获取业务 ID。
BusinessObject 控制器(新路由):
/**
* @Route("/{post_id}/new", name="business_object_new", methods="GET|POST")
* @ParamConverter("business", options={"id" = "post_id"})
*/
public function new(Request $request,Business $business): Response
{
$businessObject = new BusinessObject();
$businessID = $business->getId();
$form = $this->createForm(BusinessObjectType::class, $businessObject,array(
'business_ID'=>$businessID,
));
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($businessObject);
$em->flush();
return $this->redirectToRoute('business_object_index');
}
return $this->render('business_object/new.html.twig', [
'business_object' => $businessObject,
'business'=>$business,
'form' => $form->createView(),
]);
}
BusinessObjectType:
class BusinessObjectType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('object',TextType::class)
->add('complement')
->add('status')
->add('durationExpected')
->add('durationAchieved')
->add('client')
->add('projectManager')
->add('business',HiddenType::class,array(
'data' => $options['business_ID']
))
;
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => BusinessObject::class,
'business_ID'=>Business::class
]);
}
}
使用这段代码,我得到一个错误 Expected argument of type "App\Entity\Business or null", "string" given.
我认为这与我的表单中的函数 configureOptions() 有关
方法可以是:
public function new(Request $request,Business $business): Response
{
$businessObject = new BusinessObject();
$form = $this->createForm(BusinessObjectType::class, $businessObject);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
// I suppose your setter is `setBusiness`, otherwise use more suitable one
$businessObject->setBusiness($business);
$em = $this->getDoctrine()->getManager();
$em->persist($businessObject);
$em->flush();
表单生成器是:
builder
->add('object',TextType::class)
->add('complement')
->add('status')
->add('durationExpected')
->add('durationAchieved')
->add('client')
->add('projectManager'); // No business field
另一个选择是 embed BusinessType
表单到 BusinessObjectType
,你可以阅读更多关于表单嵌入 here.
我有一个业务实体和一个 BusinessObject 实体,我想在创建新的 BusinessObject 时将 BusinessObject link 到当前业务。
例如,如果我的路线是 business/{id}/object/new
,我希望对象与业务相关(感谢 id)。
在我的 BusinessObject 控制器中,我设法使用 @ParamConverter
来获取业务 ID。
在我的 BusinessObject 表单中,我将 HiddenType 放入我的业务条目中,因为我不希望它出现,并将 data
设置为 business_ID。
我在 configureOptions 中挣扎以获取业务 ID,我不知道如何从这里获取业务 ID。
BusinessObject 控制器(新路由):
/**
* @Route("/{post_id}/new", name="business_object_new", methods="GET|POST")
* @ParamConverter("business", options={"id" = "post_id"})
*/
public function new(Request $request,Business $business): Response
{
$businessObject = new BusinessObject();
$businessID = $business->getId();
$form = $this->createForm(BusinessObjectType::class, $businessObject,array(
'business_ID'=>$businessID,
));
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($businessObject);
$em->flush();
return $this->redirectToRoute('business_object_index');
}
return $this->render('business_object/new.html.twig', [
'business_object' => $businessObject,
'business'=>$business,
'form' => $form->createView(),
]);
}
BusinessObjectType:
class BusinessObjectType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('object',TextType::class)
->add('complement')
->add('status')
->add('durationExpected')
->add('durationAchieved')
->add('client')
->add('projectManager')
->add('business',HiddenType::class,array(
'data' => $options['business_ID']
))
;
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => BusinessObject::class,
'business_ID'=>Business::class
]);
}
}
使用这段代码,我得到一个错误 Expected argument of type "App\Entity\Business or null", "string" given.
我认为这与我的表单中的函数 configureOptions() 有关
方法可以是:
public function new(Request $request,Business $business): Response
{
$businessObject = new BusinessObject();
$form = $this->createForm(BusinessObjectType::class, $businessObject);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
// I suppose your setter is `setBusiness`, otherwise use more suitable one
$businessObject->setBusiness($business);
$em = $this->getDoctrine()->getManager();
$em->persist($businessObject);
$em->flush();
表单生成器是:
builder
->add('object',TextType::class)
->add('complement')
->add('status')
->add('durationExpected')
->add('durationAchieved')
->add('client')
->add('projectManager'); // No business field
另一个选择是 embed BusinessType
表单到 BusinessObjectType
,你可以阅读更多关于表单嵌入 here.