使用完成处理程序按顺序做事

Doing things in sequence using completion handlers

我有三个函数需要按如下顺序运行:

  1. 从 Firebase 收集整数,将它们放入数组中,然后计算总和。一旦完成...
  2. 从 Firebase 收集不同的整数值。一旦完成...
  3. 第三个函数从函数 2 中获取值,并从函数 1 中减去它。

我知道我需要使用完成处理程序,但需要语法等方面的帮助

//第一个函数从 Firebase 中获取整数并将它们相加:

func LoadPointsCompleted(completion: @escaping(_ sumOfPointsCompleted:Int) -> Int){

    self.challengeList.removeAll()

    databaseReference = Database.database().reference()

    let userID = Auth.auth().currentUser?.uid

    let refChallenges = Database.database().reference(withPath: "Challenges").child(userID!).queryOrdered(byChild: "Status").queryEqual(toValue: "Complete")

    refChallenges.observeSingleEvent(of: .value, with: { (snapshot) in

        //if the reference have some values
        if snapshot.childrenCount > 0 {

            //clearing the list
            self.challengeList.removeAll()



            //iterating through all the values
            for Challenges in snapshot.children.allObjects as! [DataSnapshot] {
                //getting values
                let challengeObject = Challenges.value as? [String: AnyObject]
                let Points = challengeObject?["Points"] as! Int

                //creating challenge object with model and fetched values
                let challenge = pointsModel(Points: (Points as Int?)!)

                //appending it to list
                self.challengeList.append(challenge)


                let sumOfPointsCompleted = self.challengeList.reduce(0) {[=10=] + .Points}

                let sumOfPointsCompletedString = String(sumOfPointsCompleted)
                self.Calc_Earned.text = sumOfPointsCompletedString

                completion(sumOfPointsCompleted)

            }

        }

    }

    )}

// 第二个函数只是从 Firebase 的另一个位置获取一个整数值

func loadPointsRedeemed(completion: @escaping (_ Points_Redeem: Int) -> Int) {


    databaseReference = Database.database().reference()

    let userID = Auth.auth().currentUser?.uid

    databaseReference.child("Users").child(userID!).observe(DataEventType.value, with: { (snapshot) in

        let value = snapshot.value as? NSDictionary

        // let Points_Earn = value?["Points_Earned"] as? String ?? ""
        let Points_Redeem = value?["Points_Redeemed"] as! Int


        // self.Points_Earned.text = Points_Earn

        let points_redeemedString = String(Points_Redeem)
        self.Points_Redeemed.text = points_redeemedString

        // let pointsRedeemedAs = Points_Redeem

        completion(Points_Redeem)

        // Do any additional setup after loading the view.
    }

)}

// 第三个函数简单地从前两个函数中获取值并减去它们

 func BalanceOfPoints(){

    let a = LoadPointsCompleted()
    let b = loadPointsRedeemed()


    let balance = a - b
    let balanceString = String(balance)

    self.Points_Balance.text = balanceString

}

但是,我在第三个函数"BalanceOfPoints"中得到一些错误如下:

调用中缺少参数 'completion' 的自变量 - 插入 'completion: <(Int) -> Int>'

当我第一次按照这里启动函数时,我不知道我的语法是否正确:

func LoadPointsCompleted(completion: @escaping(_ sumOfPointsCompleted:Int) -> Int){

和...

func loadPointsRedeemed(完成: @escaping (_ Points_Redeem: Int) -> Int) {

有人可以帮忙吗?提前致谢。

LoadPointsCompleted 将闭包作为参数(完成处理程序)

你可以给它一个 nil 完成处理程序

LoadPointsCompleted(completion: nil)

或者给它一个处理程序

LoadPointsCompleted() { sumOfPointsCompleted in

    return <#some Int#>
}

但是你在 BalanceOfPoints 中的逻辑似乎有点不对劲,因为 LoadPointsCompletedloadPointsRedeemed 同时被顺序调用而且实际上 return Int,只有函数的完成处理程序才会这样做。例如 completion(sumOfPointsCompleted) 可以更改为 let a = completion(sumOfPointsCompleted) 但我确定这不是您想要的。

我会将这两个函数的签名更改为

func LoadPointsCompleted(completion: @escaping(_ sumOfPointsCompleted:Int) -> Void){

func loadPointsRedeemed(completion: @escaping (_ Points_Redeem: Int) -> Void) {

然后在 BalanceOfPoints 中改为这样做

func BalanceOfPoints(){

    LoadPointsCompleted() { sumOfPointsCompleted in
        loadPointsRedeemed() { Points_Redeem in
            let balance = sumOfPointsCompleted - Points_Redeem
            let balanceString = String(balance)

            self.Points_Balance.text = balanceString
        }
    }
}

但请注意 BalanceOfPoints 现在是一个异步函数。

不确定你的问题中的第 1 步和第 2 步是否可以并行完成,但似乎可以,但按照这个答案,它们是按顺序进行的