如何从具有多个数组的 JSON 中删除多余的方括号
How do I remove the extra square bracket from JSON having multiple arrays
我试图从一个数组中获取 JSON,但我在输出中得到了一个额外的方括号。
我尝试使用 $episode[0] = $podcast->getPodcastByCategoryId($id);
但它只给出了不完整的输出意味着它给出了数组中第一次迭代的数据。如果我从 $episode 中删除 []
也会提供第一次迭代的数据。
$podList = $category->getCategoryPodcast();
if ($podList) {
foreach ($podList as $items) {
$id = $items->id;
$episode[] = $podcast->getPodcastByCategoryId($id);
}
}
echo json_encode($episode);
我希望只有一个方括号,但我得到的输出带有两个方括号。
这是我从上面的代码收到的结果:
[
[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
[
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
]
根据@splash58 和@Vinesh Goyal 的推荐,我得到这样的输出:
[[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
但是,第一个数据的方括号呢?
以下代码段使用 javascript .concat()
。这符合您想要的输出吗?
var data = [[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
[
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
];
var mergedData = data[0].concat(data[1]);
console.log(mergedData)
根据您的代码,$podcast->getPodcastByCategoryId($id);
返回一个数组,因此 t0 消除了您可以使用 array_merge
函数
的问题
$podList = $category->getCategoryPodcast();
$episode = [];
if ($podList) {
foreach ($podList as $items) {
$id = $items->id;
$episode = array_merge($episode, $podcast->getPodcastByCategoryId($id)
}
}
echo json_encode($episode);
希望对你有所帮助:)
您可以在获取
的同时合并数组
$episode = array_merge($episode, $podcast->getPodcastByCategoryId($id));
或者在转换为json
之前展平结果数组
echo json_encode(array_merge(...$episode));
我试图从一个数组中获取 JSON,但我在输出中得到了一个额外的方括号。
我尝试使用 $episode[0] = $podcast->getPodcastByCategoryId($id);
但它只给出了不完整的输出意味着它给出了数组中第一次迭代的数据。如果我从 $episode 中删除 []
也会提供第一次迭代的数据。
$podList = $category->getCategoryPodcast();
if ($podList) {
foreach ($podList as $items) {
$id = $items->id;
$episode[] = $podcast->getPodcastByCategoryId($id);
}
}
echo json_encode($episode);
我希望只有一个方括号,但我得到的输出带有两个方括号。
这是我从上面的代码收到的结果:
[
[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
[
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
]
根据@splash58 和@Vinesh Goyal 的推荐,我得到这样的输出:
[[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
但是,第一个数据的方括号呢?
以下代码段使用 javascript .concat()
。这符合您想要的输出吗?
var data = [[
{
"id": "6",
"title": "Types of loops in PHP.",
"description": "s.kfjhsdlufdgf o",
"duration": "0:05:05",
"audio": "http://demo.web/uploads/podAudio/PodAudio-2019011511270942.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190115112709469.jpg",
"category": "2",
"added_date": "माघ १, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
},
{
"id": "4",
"title": "How to remove square brackets from JSON?",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111541297.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg",
"category": "2",
"added_date": "पौष ३०, २०७५",
"category_title": "उमेर",
"author": "John Doe",
"episodes": "2"
}
],
[
{
"id": "5",
"title": "Hello World!",
"description": "",
"duration": "",
"audio": "http://demo.web/uploads/podAudio/PodAudio-20190114111937115.mp3",
"image": "http://demo.web/uploads/podImage/PodImage-20190114104302103.jpg",
"category": "1",
"added_date": "पौष ३०, २०७५",
"category_title": "गृह पृष्ठ",
"author": "John Doe",
"episodes": "1"
}
]
];
var mergedData = data[0].concat(data[1]);
console.log(mergedData)
根据您的代码,$podcast->getPodcastByCategoryId($id);
返回一个数组,因此 t0 消除了您可以使用 array_merge
函数
$podList = $category->getCategoryPodcast();
$episode = [];
if ($podList) {
foreach ($podList as $items) {
$id = $items->id;
$episode = array_merge($episode, $podcast->getPodcastByCategoryId($id)
}
}
echo json_encode($episode);
希望对你有所帮助:)
您可以在获取
的同时合并数组$episode = array_merge($episode, $podcast->getPodcastByCategoryId($id));
或者在转换为json
之前展平结果数组echo json_encode(array_merge(...$episode));