如何绘制 matplotlib/basemap 中多个 x、y 点之间的线

How to plot lines between multiple x,y points in matplotlib/basemap

我正在尝试使用底图在 matplotlib 中的 2 个不同的 X 和 Y 点之间绘制多条线。

import matplotlib.pyplot as plt
import numpy as np

Map=pd.read_excel(r'file.xlsx')

lat=Map['Start Latitude'] 
long=Map['Start Longitude'] 
lat1=Map['Fin Latitude'] 
long2=Map['Fin Longitude']

x,y=m(lon.values,lat.values)
plt=m.scatter(x,y, marker="o", latlon=False)

例如:

Line1 would be between 1x,1y and 1x1,1y1
Line3 would be between 2x,2y and 2x1,2y1
Line3 would be between 3x,3y and 3x1,3y1
etc

其中 "x"、"y"、"x1" 和 "y1" 位于不同的列中("start latitude"、"start longitude"、"fin latitude" "fin longitude").

会有 100 多条不同的线

我可以在上面绘制 "start latitude" 和 "start longitude"(使用 x,y=m(lon.values,lat.values)plt=m.scatter(x,y, marker="o", latlon=False),但无法绘制第二个点并连接一条线它。

如有任何建议,我们将不胜感激!谢谢你。

由于“100+”行,我建议在这里使用 LineCollection。当然你首先需要投影底图系统中的坐标。然后您可以将它们再次堆叠到一个 numpy 数组中并为 LineCollection.

创建段数组
import numpy as np; np.random.seed(42)
import pandas as pd
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
from matplotlib.collections import LineCollection


df = pd.DataFrame({"lon1" : np.random.randint(-15,30,10),
                   "lat1" : np.random.randint(33,66,10),
                   "lon2" : np.random.randint(-15,30,10),
                   "lat2" : np.random.randint(33,66,10)})

m = Basemap(llcrnrlon=-12,llcrnrlat=30,urcrnrlon=50,urcrnrlat=69.,
             resolution='i', projection='tmerc', lat_0 = 48.9, lon_0 = 15.3)

m.drawcoastlines(linewidth=0.72, color='gray')
m.drawcountries(zorder=0, color='gray')


lon1, lat1 = m(df.lon1.values, df.lat1.values)
lon2, lat2 = m(df.lon2.values, df.lat2.values)

pts = np.c_[lon1, lat1, lon2, lat2].reshape(len(lon1), 2, 2)
plt.gca().add_collection(LineCollection(pts, color="crimson", label="Lines"))

m.plot(lon1, lat1, marker="o", ls="", label="Start")
m.plot(lon2, lat2, marker="o", ls="", label="Fin")

plt.legend()
plt.show()