无法使用 f2py 编译函数中的 Fortran 代码

Cannot use fortran code from f2py compile function

我有以下 Fortran 代码:

    !routines.f90
    module mymodule
       contains

         function add(a, b)
             real(8), intent(in):: a
             real(8), intent(in):: b
             real(8) :: add
             add = a + b
         end function
    end module

而不是使用命令:python -m numpy.f2py -m routines -c routines.f90,我想从 python 脚本中编译,如下所示:

#main.py
import numpy as np
import numpy.f2py as f2py

with open(r'routines.f90', 'r') as f:
     source = f.read()

 f2py.compile(source, modulename='routines')

 print('OK')

但是当我尝试执行此脚本时:python main.py 我收到以下错误:

Traceback (most recent call last):
  File "main.py", line 7, in <module>
    f2py.compile(source, modulename='routines')
  File "/home/user1/anaconda3/lib/python3.6/site-packages/numpy/f2py/__init__.py", line 59, in compile
    f.write(source)
  File "/home/user1/anaconda3/lib/python3.6/tempfile.py", line 485, in func_wrapper
    return func(*args, **kwargs)
TypeError: a bytes-like object is required, not 'str'

你能告诉我这是什么问题吗?

open(r'routines.f90', 'r') 打开您的文件以阅读 text (a.k.a. str),但是,显然,f2py.compile 需要它的第一个参数是 bytes 类型。为了满足这一点,以二进制模式打开文件:

open(r'routines.f90', 'rb')

(另外,r'routines...'中的第一个r不需要,直接做'routines.f90'即可,虽然变化不大。