处理上传多个文件时的 multer.single('file') 错误
Handle multer.single('file') error when upload multiple files
我关注了Multer code:
app.post('/profile', upload.single('avatar'), function (req, res, next) {
})
应上传一个文件。但是如果一个人试图上传多个文件,如何捕获错误 MulterError: Unexpected field
?
我试过以下但没有成功:
app.post('/profile', upload.single('avatar'), function (req, res, next) {
try {
} catch (error) {
// Why cannot catch any error?
}
})
当upload.single
执行next()
时,只有它来这里,
app.post('/profile', upload.single('avatar'), function (req, res, next) {
try {
} catch (error) {
// It catches only errors from above `try block`
}
});
如果 upload.single
遇到任何错误,它不会调用 next()
而是传递给下一个侦听器。要捕获 upload.single
的任何错误,您必须在上面的 app.post(/profile)
.
之后添加它
app.use(function (err, req, res, next) {
var error = err.message;
res.status(500);
res.send({ "error": error });
});
我关注了Multer code:
app.post('/profile', upload.single('avatar'), function (req, res, next) {
})
应上传一个文件。但是如果一个人试图上传多个文件,如何捕获错误 MulterError: Unexpected field
?
我试过以下但没有成功:
app.post('/profile', upload.single('avatar'), function (req, res, next) {
try {
} catch (error) {
// Why cannot catch any error?
}
})
当upload.single
执行next()
时,只有它来这里,
app.post('/profile', upload.single('avatar'), function (req, res, next) {
try {
} catch (error) {
// It catches only errors from above `try block`
}
});
如果 upload.single
遇到任何错误,它不会调用 next()
而是传递给下一个侦听器。要捕获 upload.single
的任何错误,您必须在上面的 app.post(/profile)
.
app.use(function (err, req, res, next) {
var error = err.message;
res.status(500);
res.send({ "error": error });
});