Java 布石头剪刀程序

Question

剪刀石头布java程序。

好的，我现在遇到的唯一问题是玩家的分数直到第二个循环才更新。有什么建议么？

再次感谢 Radiodef 的帮助！！

更新了下面的代码......

import java.util.Scanner;


public class RPS_Game {

public static void main(String[] args) {
    char r = 'R';
    char p = 'P';
    char s = 'S';
    char player1 = 0;
    char player2 = 0;
    int player1Score = 0;
    int player2Score = 0;
    int playCount = 0;


    Scanner scan = new Scanner(System.in);



    while(playCount < 3) {

        System.out.print("Please enter either (R)ock, (P)aper, or (S)iccors: ");
        player1 = scan.nextLine().toUpperCase().charAt(0);
        System.out.print("Please enter either (R)ock, (P)aper, or (S)iccors: ");
        player2 = scan.nextLine().toUpperCase().charAt(0);

        int winner = winningPlayer(player1, player2);   
        if(winner == 0) {
            System.out.print("\nIt's a tie.  Nobody wins!\n");
            System.out.println("\nPlayer 1: " + (player1Score += 0));
            System.out.println("\nPlayer 2: " + (player2Score += 0));
        }
        if(winner == 1) {
            System.out.print("\nPlayer 1 wins!!\n");
            System.out.println("\nPlayer 1: " + player1Score++);    
            System.out.println("\nPlayer 2: " + (player2Score += 0));
        }
        if(winner == 2) {
            System.out.print("\nPlayer 2 wins!!\n");
            System.out.println("\nPlayer 1: " + (player1Score += 0));
            System.out.println("\nPlayer 2: " + player2Score++);    
        }   
    playCount++;
    }       
}

public static int winningPlayer(int player1,  int player2) {    

    //Player 1 wins 
    int result = 0;
    if(player1 == 'R' && player2 == 'S') {      
        result = 1;
    }
    else if(player1 == 'P' && player2 == 'R') {
        result = 1;
    }   
    else if(player1 == 'S' && player2 == 'P') {
        result = 1;
    }   
    //Player 2 wins 
    else if(player2 == 'R' && player1 == 'S') {
        result = 2;
    }
    else if(player2 == 'P' && player1 == 'R') {
        result = 2;
    }   
    else if(player2 == 'S' && player1 == 'P') {
        result = 2;
    }
    return result;
}   
}

Answer 1

好吧，看来您首先需要将调用移入循环：

while(playCount < 3) {
    System.out.print("Please enter either (R)ock, (P)aper, or (S)iccors: ");
    player1 = scan.nextLine().toUpperCase().charAt(0);
    System.out.print("Please enter either (R)ock, (P)aper, or (S)iccors: ");
    player2 = scan.nextLine().toUpperCase().charAt(0);

    // recompute the winner each time
    int winner = winningPlayer(player1, player2);
    ...
}

为了保持分数，您可以为每个玩家设置一个变量：

int player1Score = 0;
int player2Score = 0;

while (...) {
    ...

    if (winner == 1) {
        ++player1Score;
    }
    if (winner == 2) {
        ++player2Score;
    }
}

或者你可以做一些更高级的事情，比如使用数组：

int[] scores = new int[3];

while (...) {
    ...

    ++scores[ winner ];

    for (int i = 1; i < scores.length; ++i) {
        System.out.printf("Player %d score is %d.\n", i, scores[i]);
    }
}

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