想要在访问中使用两个相关表填充组合框

Want to populate a combobox with two related tables in access

我的访问数据库中有两个相关表,Table1Table2。 在表 1 中,我有“Cd_Table1”(主键)和“Cd_Table2”(外键)。 在表 2 中,我有“Cd_Table2”(主键)和“Nm_Atr”(字符串)。 我想用这两个表填充一个组合框,但是“DisplayMemberPath”需要是“Nm_Atr ”和“ValueMemberPath”需要是“Cd_Table1 ".

我的代码:

OleDbCommand cmd = new OleDbCommand("SELECT Table1.Cd_AtributosNormais, Table1.Nm_Atr, Table2.Cd_AtributosNormais FROM Table1, Table2 WHERE Table1.Cd_AtributosNormais = Table2.Cd_AtributosNormais", cn);
            OleDbDataReader reader = cmd.ExecuteReader();
            DataTable table = new DataTable();
            table.Load(reader);
            DataRow row = table.NewRow();
            row["Nm_Atr"] = "";
            table.Rows.InsertAt(row, 0);

            this.btCmbAtkBaAtr1.DataContext = table.DefaultView;
            this.btCmbAtkBaAtr1.DisplayMemberPath = "Nm_Atr";
            this.btCmbAtkBaAtr1.SelectedValuePath = "Cd_AtributosNormais";
            cmd.ExecuteNonQuery();
            reader.Close();
            reader.Dispose();
        }
        catch(Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
        finally
        {
            cn.Close();
            cn.Dispose();
        }

错误在哪里,为什么组合框不显示任何内容? 我已经打开了一个连接,我正在使用 C# 编程和访问 2010。

如果有帮助,试试这个..

OleDbCommand cmd = new OleDbCommand("SELECT Table1.Cd_AtributosNormais as Cd_AtributosNormais, Table2.Nm_Atr as Nm_Atr FROM Table1 Left outer join Table2 on Table1.Cd_AtributosNormais = Table2.Cd_AtributosNormais", cn);
            OleDbDataReader reader = cmd.ExecuteReader();
            DataTable table = new DataTable();
            table.Load(reader);
            DataRow row = table.NewRow();
            row["Nm_Atr"] = "";
            table.Rows.InsertAt(row, 0);

            this.btCmbAtkBaAtr1.DataContext = table.DefaultView;
            this.btCmbAtkBaAtr1.DisplayMemberPath = "Nm_Atr";
            this.btCmbAtkBaAtr1.SelectedValuePath = "Cd_AtributosNormais";
            cmd.ExecuteNonQuery();
            reader.Close();
            reader.Dispose();
        }
        catch(Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
        finally
        {
            cn.Close();
            cn.Dispose();
        }