如何在 C# Mongodb 强类型驱动程序中基于嵌套数组元素创建索引

Question

这个问题与的原则完全相同，但我想在 object 属性上使用强类型方法创建索引，当此 object 嵌套在 collection.

的数组中

我可以使用：

new CreateIndexModel<T>( Builders<T>.IndexKeys.Ascending( a ) )

其中 a 是一个直接访问属性.

的表达式

但我没有发现类似的内容：

Builders<Library>.Filter.ElemMatch(x => x.Author.Books, b => b.IsVerified == false));

这样我就可以将嵌套在数组中的 object 的某个字段定义为索引，该数组是 collection.

的成员

这可能吗？怎么做？

Answer 1

考虑以下数据模型：

public class Course
{
   public string Name { get; set; }
   public string Teacher { get; set; }
}

public class Student
{
  public string Name { get; set; }
  public int Age { get; set; }
  public ReadOnlyCollection<Course> Courses { get; set; }
}

您可以通过以下方式在字段 Courses 上创建升序多键索引：

using MongoDB.Driver;
using System;
using System.Collections.Generic;
using System.Threading.Tasks;

namespace ConsoleApp1
{
  public static class Program
  {
    private static MongoClient Client;
    private static IMongoDatabase Database;
    private static IMongoCollection<Student> Collection;

    public static async Task Main(string[] args)
    {
      Client = new MongoClient();
      Database = Client.GetDatabase("test-index");
      Collection = Database.GetCollection<Student>("students");

      var courses1 = new List<Course>()
      {
        new Course { Name = "Math", Teacher = "Bob" }
      }.AsReadOnly();

      var courses2 = new List<Course>()
      {
        new Course { Name = "Computer Science", Teacher = "Alice" }
      }.AsReadOnly();

      var mark = new Student
      {
        Name = "Mark",
        Courses = courses1,
        Age = 20
      };

      var lucas = new Student
      {
        Name = "Lucas",
        Courses = courses2,
        Age = 22
      };

      await Collection.InsertManyAsync(new[] { mark, lucas }).ConfigureAwait(false);


      var model = new CreateIndexModel<Student>(
        Builders<Student>.IndexKeys.Ascending(s => s.Courses));

      await Collection.Indexes.CreateOneAsync(model).ConfigureAwait(false);

      Console.WriteLine("All done !");
    }
  }
}

此查询由您创建的索引提供服务： db.students.find({Courses: {"Name": "Math", "Teacher": "Bob"}})

如果您不想在整个数组 Courses 上创建索引，而是想在嵌套对象（Course 对象）的字段 Name 上创建索引，这是方法：

using MongoDB.Driver;
using System;
using System.Collections.Generic;
using System.Threading.Tasks;

namespace ConsoleApp1
{
  public static class Program
  {
    private static MongoClient Client;
    private static IMongoDatabase Database;
    private static IMongoCollection<Student> Collection;

    public static async Task Main(string[] args)
    {
      Client = new MongoClient();
      Database = Client.GetDatabase("test-index");
      Collection = Database.GetCollection<Student>("students");

      var courses1 = new List<Course>()
      {
        new Course { Name = "Math", Teacher = "Bob" }
      }.AsReadOnly();

      var courses2 = new List<Course>()
      {
        new Course { Name = "Computer Science", Teacher = "Alice" }
      }.AsReadOnly();

      var mark = new Student
      {
        Name = "Mark",
        Courses = courses1,
        Age = 20
      };

      var lucas = new Student
      {
        Name = "Lucas",
        Courses = courses2,
        Age = 22
      };

      await Collection.InsertManyAsync(new[] { mark, lucas }).ConfigureAwait(false);


      var model = new CreateIndexModel<Student>(
        Builders<Student>.IndexKeys.Ascending("Courses.Name"));

      await Collection.Indexes.CreateOneAsync(model).ConfigureAwait(false);

      Console.WriteLine("All done !");
    }
  }
}

此查询由您创建的索引提供服务：db.students.explain("executionStats").find({"Courses.Name": "Math"})

在我的第二个示例中避免使用魔术字符串的一种可能方法是利用 nameof C# 运算符的强大功能： $"{nameof(Student.Courses)}.{nameof(Course.Name)}"

Answer 2

这是使用 MongoDB.Entities 便利库为嵌套字段创建索引的强类型方法。 [免责声明：我是作者]

using MongoDB.Entities;
using System.Collections.Generic;

namespace Whosebug
{
    public class Program
    {
        public class Parent : Entity
        {
            public Child[] Children { get; set; }
        }

        public class Child
        {
            public List<Friend> Friends { get; set; }
        }

        public class Friend
        {
            public string Name { get; set; }
        }

        static void Main(string[] args)
        {
            new DB("test");

            DB.Index<Parent>()
              .Key(p => p.Children[-1].Friends[-1].Name, KeyType.Ascending)
              .Create();

        }
    }
}

上面使用以下命令在嵌套两层的名称字段上创建升序索引：

db.Parent.createIndex({
    "Children.Friends.Name": NumberInt("1")
}, {
    name: "Children.Friends.Name(Asc)",
    background: true
})

如何在 C# Mongodb 强类型驱动程序中基于嵌套数组元素创建索引

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