为每个组值获取不同的 ID mysql

Question

我有一个结果集如下：

client_id   status
------------------
67          1
67          0
67          0
67          0
77          0

我只需要获取那些 client_id 的 latest (top) 条目是 0。

我尝试关注，但都得到了 67 and 77。 67 应该被排除在外。

SELECT DISTINCT client_id FROM
(
    SELECT client_id, status FROM client_history 
    WHERE (DATE(updated_on) BETWEEN '$from' AND '$to') 
    ORDER BY DATE(updated_on) DESC
) as ch
WHERE status = 0
GROUP BY client_id

如何设置条件，以便我只能获取那些 status 为 0 的记录？

Answer 1

使用不存在的相关子查询

select distinct client_id
from lient_history a
where not exists (select 1 from lient_history b where a.client_id=b.client_id 
  and status=1) 
and (DATE(updated_on) BETWEEN '$from' AND '$to')

Answer 2

要获取最新条目，您可以使用相关子查询：

select ch.*
from client_history ch
where ch.updated_on = (select max(ch2.updated_on)
                       from client_history ch2
                       where ch2.client_id = ch.client_id and
                             date(updated_on) between ? and ?
                      );

请注意，这使用参数占位符 (?) 而不是字符串替换来传递值。

为此，您只需添加：

and status = 0

用于您想要的过滤。

Answer 3

请尝试以下一种，我认为它会解决您的问题。

Declare @FromDate Date, @ToDate Date
Set @FromDate = -- whatever date range you wanted to give
Set @ToDate =  -- whatever date range you wanted to give
SELECT DISTINCT client_id FROM dbo.Client_history 
WHERE cast(updated_on as DATE)>=@FromDate and cast(updated_on as DATE)<=@ToDate
AND status = 0
ORDER BY DATE(updated_on) DESC

为每个组值获取不同的 ID mysql

Get distinct ids for each group value mysql

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