根据文件名仅提取最近的文件

Question

我只想从已更新的文件中解压最新的文件。这是我的代码：


def main():

    dest_dir = 'C:/Users/PycharmProjects/kpi/flats'
    zip_file = 'Z:/OUT.zip'

    with ZipFile(zip_file) as zipObj:
        for zip_info in zipObj.infolist():
            if zip_info.filename[-1] == '/':
                continue
            if zip_info.filename.startswith('homeware/R2D2/DATA/OUT/Flat/FlatFile_r2d2_01012018'):
                print(zip_info.filename)
                zip_info.filename = os.path.basename(zip_info.filename)
                zipObj.extract(zip_info,dest_dir)

提取的文件是：

homeware/R2D2/DATA/OUT/Flat/Flat_01012018_180216.csv
homeware/R2D2/DATA/OUT/Flat/Flat_01012018_210147.csv
homeware/R2D2/DATA/OUT/Flat/Flat_01012018_230148.csv

但我只想要基于文件名而不是元数据的最后一个

Answer 1

所以我所做的不是在每次迭代时提取，而是将满足 'if' 要求的文件附加到列表中。然后我提取了该列表的最大值，这是我正在寻找的文件。这是更新后的代码：

def main():

    dest_dir = 'C:/Users/mbelahce040119/PycharmProjects/kpi/flats'
    zip_file = 'Z:/DATA/OUT/COMMON_2018/201810/OUT_201810.zip'

    with ZipFile(zip_file) as zipObj:
        files_sat = list()
        for zip_info in zipObj.infolist():
            if zip_info.filename[-1] == '/':
                continue
            if zip_info.filename.startswith('homeware/R2D2/DATA/OUT/Flat/FlatFile_r2d2_01012018'):
                print(zip_info.filename)
                files_sat.append(zip_info.filename)
                zip_info.filename = os.path.basename(max(files))
        zipObj.extract(max(files_sat), dest_dir)

根据文件名仅提取最近的文件

Extract only most recent file based on filename

python

filenames

max