Laravel Eloquent GroupBy 抛出 SQL 错误

Question

当我手动运行以下 SQL 时，我得到了预期的结果，没有错误

select * from `crawl_results` 
    where `user_id` = 1 and `website_id` = 1 
    and `item_state` != 'OK' group by `destination_url` 
    limit 30 offset 0

但是当我运行这个在 Eloquent...

self::where('user_id', Auth::id())
    ->where('website_id', $scanID)
    ->where('item_state', '!=' , 'OK')
    ->groupby('destination_url')->paginate(30)

它产生这个错误：

SQLSTATE[42000]: Syntax error or access violation: 1055 'link_checker.crawl_results.id' isn't in GROUP BY (SQL: select * from crawl_results where user_id = 1 and website_id = 1 and item_state != OK group by destination_url limit 30 offset 0)

不确定产生该错误的抽象背后发生了什么？

Answer 1

您应该转到 config\database.php 并将 strict 更改为 false

'mysql' => [
   ...
   'strict' => false,
   ...
 ]

Answer 2

将您的查询更改为查询构建器查询

DB::table('crawl_results')->where('user_id', Auth::id())->where('website_id', $scanID)->where('item_state', '!=' , 'OK')->groupby('destination_url')->paginate(30);

它应该可以正常工作。

documentation中提到分页时GROUP BY不能高效执行

Currently, pagination operations that use a groupBy statement cannot be executed efficiently by Laravel. If you need to use a groupBy with a paginated result set, it is recommended that you query the database and create a paginator manually.

Laravel Eloquent GroupBy 抛出 SQL 错误

Laravel Eloquent GroupBy throwing SQL error

php

laravel

eloquent

laravel-5

laravel-query-builder