如何为所需的附加输出正确格式化代码？

Question

我正在编写新代码，但无法获得所需的输出。该代码读取 html 文件并查找标签。它只输出 url 。我插入额外的代码来完成 link。我试图在字符串中插入 url 两次。

####### Parse for <a> tags and save ############
with open("page1.html", 'r') as htmlb:
    soup2 = BeautifulSoup(htmlb, 'lxml')
links = []
for link in soup2.findAll('a', attrs={'href':   re.compile("^https://")}):
    links.append('<a href="'+link.get('href')+'">'"{link}"'</a><br>')

time.sleep(.1)

with  open("page-2.html", 'w') as html:
    html.write('{links}\n'.format(links=links))

Answer 1

我猜这让我想要，但不完全是。我宁愿看到它写成“https://whatever.com/text/text/”也不愿看到"whatever.com/text/text"

####### Parse for <a> tags and save ############
with open("page1.html", 'r') as htmlb:
    soup2 = BeautifulSoup(htmlb, 'lxml')
links = []
for link in soup2.findAll('a', attrs={'href':   re.compile("^https://")}):
links.append('{0}</a><br>'.format(link,link))

with  open("page-2.html", 'w') as html:
    html.write('{links}\n'.format(links=links))

Answer 2

这应该会为您提供所需的 html 输出文件：

import re
from bs4 import BeautifulSoup
import html 

with open("page1.html", 'r') as htmlb:
    soup2 = BeautifulSoup(htmlb, 'lxml')



with open("page2.html", 'w') as h:
    for link in soup2.find_all('a'):
       h.write("<a href=\"{}\">{}</a><br>".format(link.get('href'),link.get('href')))

如何为所需的附加输出正确格式化代码？

How do I properly format code for desired appending output?

python-2.x