如何在 django models.py 中使用 ListField 而在 settings.py 中使用 DJONGO 作为引擎

Question

我的json数据是这样的

{
    "Batch Year": 1998 - 1999,
    "Roll Nos": ["36", "125"],
    "Student Names": ["xyz", "xxy"],
    "Project Name": "IMPLEMENTATIONOF NETWORK SECURITY BY VIRTUAL PRIVATE NETWORK (VPN)",
    "Project Supervisor": "abc",
    "External Supervisor": "aaa",
    "Co-Supervisor": "None",
    "Project Id": 155
}

对于此数据，我在 models.py 中为卷号和学生姓名定义了 ListFields，但是当我使用管理面板向我的数据库中添加数据时，我遇到了错误：

"Exception Value: A Formless Field cannot be modified from Django Admin."

settings.py

DATABASES = {
    'default': {
        'ENGINE': 'djongo',
        'NAME': 'fypcis_db',
    }

models.py

from __future__ import unicode_literals
from djongo import models
import djongo

class students(models.Model):
    batch_year = models.IntegerField(db_column='Batch Year')  # Field name made lowercase.
    roll_nos = djongo.models.ListField(db_column='Roll Nos',default=True)  # Field name made lowercase.
    student_name = djongo.models.ListField(db_column='Student Names',default=True)  # Field name made lowercase.
    project_name = models.CharField(max_length=250, db_column='Project Name',default=True)  # Field name made lowercase.
    project_supervisor = models.CharField(max_length=250, db_column='Project Supervisor',default=True)  # Field name made lowercase.
    external_supervisor = models.CharField(max_length=250,db_column='External Supervisor',default=True)  # Field name made lowercase.
    co_supervisor = models.CharField(max_length=250,db_column='Co-Supervisor',default=True)  # Field name made lowercase.
    project_id = models.IntegerField(db_column='Project Id')  # Field name made lowercase.

请帮我解决这个错误。提前致谢

我正在使用 django 2.2 和 djongo 作为引擎

Answer 1

https://nesdis.github.io/djongo/using-django-with-objectid-field/ ArrayModelField 和 ArrayReferenceField 要求列表中的所有模型都属于同一类型。 MongoDB 允许在嵌入式数组中保存任意数据。 ListField 在这种情况下很有用。列表字段不能在 Django Admin 中表示，只能在 python 脚本中使用。

如何在 django models.py 中使用 ListField 而在 settings.py 中使用 DJONGO 作为引擎

How to use ListField in django models.py while using DJONGO as engine in settings.py

django

mongodb

djongo

django-2.2