跨 2 个表查找不同的值不起作用

Finding Distinct Values across 2 tables is not working

我有 2 个 table(我只显示了 select 个字段):

Table答:

    <LOCATION CODE>
    ACT   
    NSWNS    
    OSUSA
    Parra
    Parra
    Parra
    ACT
    ACT

Table B(A查找table):

<CODE>    <DESCRIPTION>
ACT        Australian Capital Territory
NSWNS      New South Whales - North South
OSUSA      Overseas - USA
Parra      Parramatta

"Description" 是 'text' 类型。 "Code" 属于 'varchar' 类型。 "location" 是 t_code_key.

的一种

我正在尝试对这两个 table 执行连接,以便我从 Table A long 收到 'Code' 项目的唯一列表以及来自 TableB.

我想得到这样的东西:

<CODE>   <DESCRIPTION>
ACT      Australian Capital Territory
Parra    Parramatta
NSW      New South Whales

我已经尝试了我写的以下两个查询,但我没有得到任何运气只是错误:

select mp.location, ct.description
from 
    (select DISTINCT CAST(description AS VARCHAR(MAX)) AS ct FROM code_table)
    full outer JOIN
    (select DISTINCT location from mailout_profile) as mp 
        on ct.code = mp.location;

select mp.location, ct.description
from 
    (select DISTINCT convert(VARCHAR(MAX), description) AS ct FROM code_table)
    full outer JOIN
    (select DISTINCT location from mailout_profile) as mp 
        on ct.code = mp.location;

我得到的错误是:

SQL Error [156] [S0001]: Incorrect syntax near the keyword 'full'.
  Incorrect syntax near the keyword 'full'.
  Incorrect syntax near the keyword 'full'.

希望得到帮助谢谢!! :)

请试试这个:

WITH r1 (loc) AS
    (SELECT DISTINCT LOCATION FROM [mailout_profile])
SELECT Code, Description FROM r1
FULL OUTER JOIN [code_table] ct ON r1.loc =  ct.Code

您可以使用以下查询来获得所需的结果 -

示例数据

Declare @TableA table
(LocationCode varchar(20))

Insert into @TableA
values

    ('ACT'   ),
    ('NSWNS' ),   
    ('OSUSA'    ),
    ('Parra'    ),
    ('Parra'    ),
    ('Parra'    ),
    ('ACT'  ),
    ('ACT'  )


Declare @TableB table
(Code varchar(20), Description varchar(100))

Insert into @TableB
values
('ACT'    ,  'Australian Capital Territory'   ),
('NSWNS'  ,  'New South Whales - North South' ),
('OSUSA'  ,  'Overseas - USA'                 ),
('Parra'  ,  'Parramatta'                     )

查询

select DISTINCT LocationCode, [Description] 
From @TableA a inner join @TableB b on a.LocationCode = b.Code