如何通过在 codeigniter 中仅发送参数来编写用于获取记录的函数？

Question

我有 100 个表或可能更多，我总是需要在我的应用程序中始终从各种 table.So 为每个查询编写函数来获取记录，它不是很好的编码标准。

 $this->db->select();
    $this->db->from("table1");
    $query = $this->db->get();
    return $query->result_array();


    $this->db->select();
    $this->db->from("table2");
    $query = $this->db->get();
    return $query->result_array();


    $this->db->select();
    $this->db->from("table1");
    $this->db->where("id",10);
    $query = $this->db->get();
    return $query->result_array();

我想要好的编码标准。

Answer 1

您的代码实际上可以在 1 行中

  $query= $this->db->get('table1')->result_array();

  $query= $this->db->get_where('table1', array('id'=>3,'name'=>'tom'))->result_array();

或者如果你真的想要一个函数

function getData($table){
    $query=$this->db->get($table)->result_array();
    return $query;

}

$data= getData('table1');

Answer 2

在控制器中写入此代码。

$data = $this->common_model->getRecords("table_name", "*", array("field1" => $this->input->post('user_name')));

这将是您在模型中的功能（即 common_model）。

public function getRecords($table, $fields = '', $condition = '', $order_by = '', $limit = '', $debug = 0) {

            $str_sql = '';
            if (is_array($fields)) {  #$fields passed as array
                $str_sql.=implode(",", $fields);
            } elseif ($fields != "") {   #$fields passed as string
                $str_sql .= $fields;
            } else {
                $str_sql .= '*';  #$fields passed blank
            }

            $this->db->select($str_sql, FALSE);

            if (is_array($condition)) {  #$condition passed as array
                if (count($condition) > 0) {
                    foreach ($condition as $field_name => $field_value) {
                        if ($field_name != '' && $field_value != '') {
                            $this->db->where($field_name, $field_value);
                        }
                    }
                }
            } else if ($condition != "") { #$condition passed as string
                $this->db->where($condition);
            }

            if ($limit != "")
                $this->db->limit($limit);#limit is not blank

            if (is_array($order_by)) {
                $this->db->order_by($order_by[0], $order_by[1]);  #$order_by is not blank
            } else if ($order_by != "") {
                $this->db->order_by($order_by);  #$order_by is not blank
            }


            $this->db->from($table);  #getting record from table name passed
            $query = $this->db->get();

            if ($debug) {
                die($this->db->last_query());
            }
            $error = $this->db->_error_message();
            $error_number = $this->db->_error_number();
            if ($error) {
                $controller = $this->router->fetch_class();
                $method = $this->router->fetch_method();
                $error_details = array(
                    'error_name' => $error,
                    'error_number' => $error_number,
                    'model_name' => 'common_model',
                    'model_method_name' => 'getRecords',
                    'controller_name' => $controller,
                    'controller_method_name' => $method
                );
                $this->common_model->errorSendEmail($error_details);
                redirect(base_url() . 'page-not-found');
            }
            return $query->result_array();
        }

我使用这段代码来获取记录。您只需要传递 table 名称、字段名称、条件和限制。

如何通过在 codeigniter 中仅发送参数来编写用于获取记录的函数？

how to write a function for fetching the record by sending only parameters in codeigniter?

php

mysql

codeigniter