关闭 Kivy 中的弹出窗口 Window

Question

我正在尝试关闭 KV 语言的弹出窗口 window。我曾尝试创建一个函数，但在调用弹出窗口 window 的实例时遇到问题，因为它不是它自己的 class 对象。我也尝试过使用工厂模块，但这也不起作用，因为出于某种原因，这只会让我在弹出 window 中使用一个小部件。下面是我的代码：

Python 文件:

class SettingsWindow(Screen):
pretty_list_people = StringProperty ("")
pretty_list_jobs = StringProperty ("")

def get_Jobs(self):
    return WindowManager.jobs

def get_People(self):
    return WindowManager.people

def Pretty_Print_People(self, ppl_list):
    self.pretty_list_people = ""
    for person in ppl_list:
        self.pretty_list_people += person + "\n"

def Pretty_Print_Jobs(self, job_list):
    self.pretty_list_jobs = ""
    for job in job_list:
        self.pretty_list_jobs += job + "\n"

def show_popup(self):
    show = PopupAddJob()
    popupWindow = Popup(title="Add Job", content=show, size_hint=(None, None), size=(200, 200))
    popupWindow.open()

def dismiss_popup(self):
    self.popupWindow.dismiss()

kv 文件：

<PopupAddJob>:
Label:
    text: "You pressed a button"
    size_hint: 0.6, 0.2
    pos_hint: {"x":0.2, "top":1}
TextInput:
    id: add_job
    multiline: False
    size_hint: 0.6, 0.2
    pos_hint: {"x":0.2, "y":0.5}
Button:
    text: "Close"
    on_press:add_job.focus=True
    on_press: SettingsWindow.dismiss_popup() # <<<<<<<<<< *** PROBLEM IS HERE ***
    size_hint: 0.6, 0.2
    pos_hint: {"x":0.2, "y":0.3}

Answer 1

在您的 dismiss_popup() 方法中您引用了 self.popupWindow，但您还没有创建这样的属性。也许您应该在 show_popup() 方法中创建该引用：

def show_popup(self):
    show = PopupAddJob()
    self.popupWindow = Popup(title="Add Job", content=show, size_hint=(None, None), size=(200, 200))
    self.popupWindow.open()

关闭 Kivy 中的弹出窗口 Window

Dismiss Pop Up Window in Kivy

python

class

popup

dismiss

kivy