org.hibernate.hql.internal.ast.QuerySyntaxException：连接异常的预期路径

Question

我正在尝试使用休眠编写 jpql 查询。我在@Repository

中有这样的查询

@Query(value = "select p from Product p inner join ProductsUser pu on p.prosuctId = pu.productId where pu.userId = :uuid")

但是我得到一个例外

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: Path expected for join! [select p from com.example.api.dto.ProductDto p inner join ProductsUsersDto pu on p.prosuctId = pu.productId where pu.userId = :uuid]

Answer 1

您不需要指定 JOIN ... ON-子句，因为它已在实体类中配置。所以查询比较简单，像这样：

@Query("select p from Product p join p.productsUser pu where pu.userId = :uuid")

org.hibernate.hql.internal.ast.QuerySyntaxException：连接异常的预期路径

org.hibernate.hql.internal.ast.QuerySyntaxException: Path expected for join exeption

java

postgresql

jpql