如何删除 TypeORM 和 Nest.js 中的嵌套实体

How to delete nested entities in TypeORM and Nest.js

我有一对多关系:

class User {
    @PrimaryGeneratedColumn()
    id: number;

    @Column()
    name: string;

    @OneToMany(() => Phone, phone => phone.user, {cascade: true})
    phones?: Phone[];
}

假设数据库中的当前数据如下:用户有两个 phone 号码:

{
  "id": 1,
  "name": "Jhon",
  "phones": [
    {"id": 1, "phone":  "123456"},
    {"id": 2, "phone":  "567809"}
  ]
}

我构建了 UI(网络界面),我想从网络界面中删除用户配置文件中的 phone 号码。所以我这样做了,下面的 POST 请求来自 UI:第二个 phone 号码已删除

{
  "id": 1,
  "name": "Jhon",
  "phones": [
    {"id": 1, "phone":  "123456"}
  ]
}

如何从数据库中删除 phone 号码 id=2? 我使用 Nest CRUD 模块,正如我从源代码中了解到的那样,它只是将来自请求的新数据与来自数据库的当前数据合并,因此将来自数据库的两个 phone 数字与来自请求的唯一 phone 数字合并给我们再次排列 phone 个数字,但没有删除任何内容:皱眉: 我试着手动做了,代码很多!

  @Override()
  async updateOne(
    @ParsedRequest() req: CrudRequest,
    @ParsedBody() dto: UpdateUserDto,
    @Param('id') id: number,
  ): Promise<Shipment> {

    // use standart Nest.js way to save new user data into database
    await this.service.updateOne(req, dto);

    // load fresh user data from database
    const user = await this.service.findOne(id);

    const phonesFromUi = dto.phones;
    const phonesToBeDeleted = [];
    // loop phone numbers from database - detect which to be deleted
    user.phones.forEach((phoneFromDb) => {
      const hasThisPhoneOnUi = phonesFromUi.find((phoneFromUi) => phoneFromUi.id === phoneFromDb.id);
      if (!hasThisPhoneOnUi) {
        // looks like this phone number was deleted on ui, so delete it from database too
        phonesToBeDeleted.push(phoneFromDb);
      }
    });
    // actually delete phone numbers from database
    await this.connection.getRepositoryFor(Phone).remove(phonesToBeDeleted);

    // reload fresh user data from database to get fresh list of phone numbers after delition some of them
    const user = await this.service.findOne(id);

    return user;
  }

有没有办法通过 TypeORM 内置函数或方法来做到这一点?如何从嵌套数组中删除一些元素?

typeorm 对连接更新没有很好的支持,我建议你做的是接收 phones 参数并获取 select 与 UserId 相关的电话,然后删除不在新数组中的 ID:

const phones = await this.phoneRepository.find({userId:1});
const toDeletePhones = phones.filter((element)) => {
  return updatePhones.indexOf(element) === -1;
}
this.phoneRepository.remove(toDeletePhones);

然后继续更新用户,或者您甚至可以在此之前完成