array_splice() ：将数组插入索引为 [PHP] 的二维数组中

Question

我正在尝试将一个数组插入二维数组的特定位置。根据手册，我应该可以使用 array_splice() 执行此操作，但它只会删除我的接收数组的内容而不会插入。

我想得到一个包含 $receivingArray 的所有值（数组）加上新值（数组）的数组。

我做错了什么？？

手册信息：

array array_splice ( array &$input , int $offset [, int $length [, mixed $replacement = array() ]] )

If length is specified and is zero, no elements will be removed. If replacement is just one element it is not necessary to put array() around > it, unless the element is an array itself, an object or NULL.

输入：

$newArray = array_splice($receivingArray, 0, 0, array($value));

结果：$newArray 是一个空数组

输入：

$newArray = array_splice($receivingArray, 1, 0, array($value));

结果：$newArray 是一个空数组

这个输入：

print_r($receivingArray);
print_r(array($value));
$newArray = array_splice($receivingArray, 1, 1, array($value));
print_r($newArray);

给出：（有趣的）

Array
(
    [0] => Array
        (
            [id] => 1
            [primaryID] => 0
            [category_id] => 1
            [title] => sports
            [description] => 
            [selected] => 
            [level] => 0
        )

    [1] => Array
        (
            [id] => 4
            [primaryID] => 0
            [category_id] => 0
            [title] => programming
            [description] => 
            [selected] => 
            [level] => 0
        )

)
Array
(
    [0] => Array
        (
            [id] => 2
            [primaryID] => 1
            [category_id] => 1
            [title] => soccer
            [description] => 
            [selected] => 
            [level] => 1
        )

)
Array
(
    [0] => Array
        (
            [id] => 4
            [primaryID] => 0
            [category_id] => 0
            [title] => programming
            [description] => 
            [selected] => 
            [level] => 0
        )

)

Answer 1

来自 array_splice()

的文档

Return Values

Returns the array consisting of the extracted elements.

$newArray = array_splice($receivingArray, 0, 0, array($value));

array_splice 修改其输入，因此您要查找的结果在 $receivingArray 而不是 $newArray

Answer 2

我错过了 array_slice() 实际上并不 return 它的输出，而是作用于通过引用传递的接收数组本身这一事实。没注意到手册规范中第一个参数前面有一个符号。

这个输入：

print_r($receivingArray);
print_r(array($value));
array_splice($receivingArray, 0, 0, array($value));
print_r($receivingArray);

给出正确的结果：

Array 
(
    [0] => Array
        (
            [id] => 1
            [primaryID] => 0
            [category_id] => 1
            [title] => sports
            [description] => 
            [selected] => 
            [level] => 0
        )

    [1] => Array
        (
            [id] => 4
            [primaryID] => 0
            [category_id] => 0
            [title] => programming
            [description] => 
            [selected] => 
            [level] => 0
        )

)
Array
(
    [0] => Array
        (
            [id] => 2
            [primaryID] => 1 
            [category_id] => 1
            [title] => soccer
            [description] => 
            [selected] => 
            [level] => 1
        )

)
Array
(
    [0] => Array
        (
            [id] => 1
            [primaryID] => 0
            [category_id] => 1
            [title] => sports
            [description] => 
            [selected] => 
            [level] => 0
        )

    [1] => Array
        (
            [id] => 2
            [primaryID] => 1
            [category_id] => 1
            [title] => soccer
            [description] => 
            [selected] => 
            [level] => 1
        )

    [2] => Array
        (
            [id] => 4
            [primaryID] => 0
            [category_id] => 0
            [title] => programming
            [description] => 
            [selected] => 
            [level] => 0
        )

)

array_splice() ：将数组插入索引为 [PHP] 的二维数组中

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