在数组 php / mysql 中排列值

Question

我正在将数据从 mysqli 导出到 google firebase 数据库。在 firebase table 中，名为 siteGeoCode（纬度和经度）的列之一具有数组格式的值，如 [17.426083,78.439241]。但是在 mysqli table 中有两个单独的列用于纬度和经度。我正在尝试获取如下记录并将其转换为数组格式。

$emp_array = array();
$sel_query = "select companyId,countryCode,createdBy,createdDat,`latitude`,`longitude`,siteName,`status` from customers limit 0,3";
$res = mysqli_query($mysqliConn,$sel_query);
while($sel_row = mysqli_fetch_assoc($res))
{
    $emp_array[]  = $sel_row;
    $lat_array['siteGeoCode'][0] = $sel_row['latitude'];
    $lat_array['siteGeoCode'][1] = $sel_row['longitude'];
    array_push($emp_array,$lat_array);
}

//输出

[0] => Array
(
[companyId] => iArwfGLC1lE6x3lO24cb
[countryCode] => 91
[createdBy] => X54P6gVJ7dA4Fi2fjEmc
[createdDate] => 2019-08-20 00:58:08
[latitude] => 15.6070347
[longitude] => 79.6146273
[siteName] => Ongole
[status] => 1
)

[1] => Array
(
[siteGeoCode] => Array
    (
        [0] => 15.6070347
        [1] => 79.6146273
    )

)

[2] => Array
(
[companyId] => YPbhSLWQfAR6ThhszSAf
[countryCode] => 91
[createdBy] => iArwfGLC1lE6x3lO24cb
[createdDate] => 2019-09-10 22:37:08
[latitude] => 
[longitude] => 
[siteName] => Madhap
[status] => 
)

[3] => Array
(
[siteGeoCode] => Array
    (
        [0] => 
        [1] => 
    )

)

但我想要的输出应该如下所示

[0] => Array
(
[companyId] => iArwfGLC1lE6x3lO24cb
[countryCode] => 91
[createdBy] => X54P6gVJ7dA4Fi2fjEmc
[createdDate] => 2019-08-20 00:58:08
[siteGeoPoint] => Array
    (
        [0] => 15.6070347
        [1] => 79.6146273
    )
[siteName] => Ongole
[status] => 1
)

[1] => Array
(
[companyId] => YPbhSLWQfAR6ThhszSAf
[countryCode] => 91
[createdBy] => iArwfGLC1lE6x3lO24cb
[createdDate] => 2019-09-10 22:37:08
[siteGeoPoint] => Array
    (
        [0] => 
        [1] => 
    )
[siteName] => Madhap
[status] => 
)

How can I achieve this ? Any help would be greatly appreciated. Thanks in advance

Answer 1

如果您想将 latitude/longitude 列的结果放入结果分组中，请对该行进行操作，然后将其添加到您的结果集中，如下所示。

$result = [];
while ($row = mysqli_fetch_assoc($res)) {
    // group geo
    $row['siteGeoCode'] = [
        $row['latitude'],
        $row['longitude']
    ];
    // unset uneeded
    unset($row['latitude'], $row['longitude']);

    // place in result
    $result[] = $row;
}

Answer 2

您可以使用以下代码。

$output_array = array();
while($sel_row = mysqli_fetch_assoc($res)) {


$output_array[] = array(
          'companyId' => $sel_row['companyId'],
          'countryCode' => $sel_row['countryCode'],
          'createdBy' => $sel_row['createdBy'],
          'createdDate' => $sel_row['createdDate'],
          'siteGeoPoint' => array($sel_row['latitude'], $sel_row['longitude']),
          'siteName' => $sel_row['siteName'],
          'status' => $sel_row['status'],
        );
    }
print_r($output_array);

你可以看到你和我使用数组的区别。从你的输出我猜你打印了不同的数组。

希望代码能得到你想要的结果！

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