Return 基于两个条件的每个唯一 ID 的不同值的多个 COUNT 字段

Question

我正在尝试使用 MySQL 中的一些日志记录数据，我希望能够在其中告诉每个人不同的成功请求、不同的不成功请求、非不同的成功请求的计数请求，以及所有满足额外全局标准的不明确的不成功请求。

这是代表原始 table 的虚构数据示例：

+--------------+--------+---------------+----------+------+
| request_date | client |    request    | response | site |
+--------------+--------+---------------+----------+------+
| 10/30/2018   | Amy    | RE_food       |      200 | MD   |
| 10/30/2018   | Amy    | RE_food       |      200 | MD   |
| 10/30/2018   | Amy    | RE_transport  |      200 | MD   |
| 10/30/2018   | Amy    | RE_assistance |      404 | MD   |
| 10/30/2018   | Amy    | OA_assistance |      404 | MD   |
| 10/30/2018   | Bob    | RE_food       |      200 | MD   |
| 10/30/2018   | Dan    | RE_food       |      404 | MD   |
| 10/30/2018   | Dan    | RE_food       |      404 | SE   |
| 10/30/2018   | Mike   | RE_transport  |      200 | SE   |
| 10/30/2018   | Sally  | RE_food       |      404 | SE   |
| 10/30/2018   | Sally  | OA_food       |      404 | MD   |
| 10/30/2018   | Zeb    | RE_assistance |      404 | MD   |
| 10/30/2018   | Zeb    | OA_assistance |      404 | MD   |
+--------------+--------+---------------+----------+------+

我想编写一个查询 return

+--------+-----------+------------+----------+-----------+
| client | unique_OK | unique_404 | total_OK | total_404 |
+--------+-----------+------------+----------+-----------+

其中唯一表示仅计算不同的客户端、请求、响应分组。它将 return 结果

+--------+-----------+------------+----------+-----------+
| client | unique_OK | unique_404 | total_OK | total_404 |
+--------+-----------+------------+----------+-----------+
| Amy    |         2 |          1 |        3 |         1 |
| Bob    |         1 |          0 |        1 |         0 |
| Dan    |         0 |          1 |        0 |         1 |
| Mike   |         0 |          0 |        0 |         0 |
| Sally  |         0 |          0 |        0 |         0 |
| Zeb    |         0 |          1 |        0 |         1 |
+--------+-----------+------------+----------+-----------+

（请注意，在上面显示的所有四个列中，为了清楚地说明该过程，我向客户显示了 0 个计数；如果他们不包含在响应中也没关系。）

我试过类似这样的查询但没有用，但希望它对我正在尝试做的事情有意义：

SELECT client AS person, 
COUNT(DISTINCT request WHERE response = '200') AS unique_OK, 
COUNT(DISTINCT request WHERE response = '404') AS unique_404 
COUNT(WHERE response = '200') as total_OK,
COUNT(WHERE response = '404') as total_404
FROM transactions 
WHERE request like '%RE%' and site = MD and DATE_FORMAT(request_date, '%Y%m%d')='20181030';

Answer 1

使用条件聚合：

select
    client,
    count(distinct case when response = 200 then request end) unique_ok,
    count(distinct case when response = 404 then request end) unique_404,
    sum(response = 200) total_ok,
    sum(response = 404) total_404
from mytable
where 
    request like '%RE%'
    and site = 'MD' 
    and request_date = '2018-10-30'
group by client

Demo on DB Fiddle:

| client | unique_ok | unique_404 | total_ok | total_404 |
| ------ | --------- | ---------- | -------- | --------- |
| Amy    | 2         | 1          | 3        | 1         |
| Bob    | 1         | 0          | 1        | 0         |
| Dan    | 0         | 1          | 0        | 1         |
| Zeb    | 0         | 1          | 0        | 1         |

Return 基于两个条件的每个唯一 ID 的不同值的多个 COUNT 字段

Return multiple COUNT fields for distinct values per a unique ID based on two criteria conditions

mysql

sql

count

distinct

where-clause