为什么 pthread_mutex_t 结构在 gdb 中全为零？

Question

什么导致 pthread_mutex_t 结构全为零？ gdb 会话中死锁 ARM 测试应用程序的核心：

[Switching to thread 3 (LWP 3587)]
#0  __lll_lock_wait (futex=futex@entry=0x2105c <one_mutex>, private=0) at lowlevellock.c:46
46  lowlevellock.c: No such file or directory.
(gdb) f 1
#1  0xaf973818 in __GI___pthread_mutex_lock (mutex=0x2105c <one_mutex>) at pthread_mutex_lock.c:81
81  pthread_mutex_lock.c: No such file or directory.
(gdb) p mutex
 = (pthread_mutex_t *) 0x2105c <one_mutex>
(gdb) p (pthread_mutex_t ) 0x2105c
 = {
  __data = {
    __lock = 0,
    __count = 0,
    __owner = 0,
    __kind = 0,
    __nusers = 0,
    {
      __spins = 0,
      __list = {
        __next = 0x0
      }
    }
  },
  __size = '[=11=]0' <repeats 23 times>,
  __align = 0
}

Answer 1

pthread_mutex_t 用于所有互斥类型，它的一些成员只用于特定的互斥类型。

owner 至少为以下互斥类型设置了成员：

PTHREAD_MUTEX_ERRORCHECK_NP
PTHREAD_MUTEX_RECURSIVE_NP

有关详细信息，请参阅 glibc implementation of pthread_mutex_trylock。

为什么 pthread_mutex_t 结构在 gdb 中全为零？

Why is the pthread_mutex_t struct all zeros in gdb?

linux

gdb

mutex

arm

glibc