MongoDB 罗盘：select 个不同的字段值

Question

我正在使用 MongoDB Compass，但没有 Mongo Shell。我需要使用 MongoDB Compass 工具构建一个查询，以 select 来自我的集合的 "genre" 字段的不同值。

示例输入：

{"_id":{"$oid":"58c59c6a99d4ee0af9e0c34e"},"title":"Bateau-mouche sur la Seine","year":{"$numberInt":"1896"},"imdbId":"tt0000042","genre":["Documentary”,”Short”],"viewerRating":{"$numberDouble":"3.8"},"viewerVotes":{"$numberInt":"17"},"director":"Georges Mlis"}
{"_id":{"$oid":"58c59c6a99d4ee0af9e0c340"},"title":"Watering the Flowers","year":{"$numberInt":"1896"},"imdbId":"tt0000035","genre":["Short”],"viewerRating":{"$numberDouble":"5.3"},"viewerVotes":{"$numberInt":"33"},"director":"Georges M�li�s"}
{"_id":{"$oid":"58c59c6a99d4ee0af9e0c34a"},"title":"The Boxing Kangaroo","year":{"$numberInt":"1896"},"imdbId":"tt0000048","genre":["Short”],"viewerRating":{"$numberDouble":"5.2"},"viewerVotes":{"$numberInt":"48"},"director":"Birt Acres"}

预期产出：纪录片，短片

Answer 1

您可以通过 Compass 中的聚合框架执行此操作，在 $group 阶段使用 $unwind and $group. The $unwind is performed to create a unique document for each element in the target array, which enables the $addToSet 运算符，然后将流派捕获为不同的元素。

管道：

[
  {
    $unwind: {
      path: '$genre',
      preserveNullAndEmptyArrays: true
    }
  },
  {
    $group: {
      _id: null,
      uniqueGenres: { $addToSet: '$genre' }
    }
  }
]

有关指南针示例，请参见下面的屏幕截图：

MongoDB 罗盘：select 个不同的字段值

MongoDB Compass: select distinct field values

mongodb

mongodb-compass