count_if (EXPSS) 在 R 中有多个条件

Question

我正在使用 expss::count_if。

虽然像这样的东西工作正常（即，仅计算值等于“1”的值）：

(number_unemployed = count_if("1",unemployed_field,na.rm = TRUE)),

这不是（即，仅计算值等于“1”或“2”或“3”的值）：

(number_unemployed = count_if("1", "2", "3", unemployed_field,na.rm = TRUE)),

count_if 使用多个条件的正确语法是什么？我在 expss 包文档中找不到任何内容。

Answer 1

您需要将它们放入一个向量中。这有效：

(number_unemployed = count_if(c("1", "2", "3"), unemployed_field), na.rm=T),

示例： ^{示例数据如下；}

library(expss)

count_if(c("1","2","3"),dt$Encounter) 
 #> 9

数据：

dt <- structure(list(Location = c("A", "B", "A", "A", "C", "B", "A", "B", "A", "A", "A"), 
                     Encounter = c("1", "2", "3", "1", "2", "3", "4", "1", "2", "3", "4")), 
                row.names = c(NA, -11L), class = "data.frame")

#    Location Encounter
# 1         A         1
# 2         B         2
# 3         A         3
# 4         A         1
# 5         C         2
# 6         B         3
# 7         A         4
# 8         B         1
# 9         A         2
# 10        A         3
# 11        A         4

count_if (EXPSS) 在 R 中有多个条件

count_if (EXPSS) with multiple conditions in R

r

count

expss